Top JEE Doubts this Week
A and B together have Rs. 1210. If 
of A's amount is equal to 
of B's amount, how much amount does B have?
- a)Rs. 460
- b)Rs. 484
- c)Rs. 550
- d)Rs. 664
Correct answer is 'B'. Can you explain this answer?
A and B together have Rs. 1210. If of A's amount is equal to of B's amount, how much amount does B have?
of A's amount is equal to of B's amount, how much amount does B have?a)
Rs. 460
b)
Rs. 484
c)
Rs. 550
d)
Rs. 664
|
Manoj Ghosh answered • Sep 09, 2019 JEE |
A+B=1210(4/15)A=(2/5)B2A=3BTherefore, A=(3B)/2and substituting, (3B/2)+B=1210and hence, 5B=2420 => B=484 Rs.
Directions: Study the following question carefully and choose the right answer.In a certain coding system, APPLE stands for ETTPI. What is the code for "DELHI"?- a)CQMND
- b)CQPLM
- c)ZAHDE
- d)HIPLM
Correct answer is option 'D'. Can you explain this answer?
Directions: Study the following question carefully and choose the right answer.
In a certain coding system, APPLE stands for ETTPI. What is the code for "DELHI"?
a)
CQMND
b)
CQPLM
c)
ZAHDE
d)
HIPLM
|
EduRev GATE answered • Jun 05, 2025 JEE |
Hence, option D is correct.
Sum of number of ions in aqueous solution of CrCl3.5NH3 and CrCl3 . 4NH3.
Correct answer is '5'. Can you explain this answer?
Sum of number of ions in aqueous solution of CrCl3.5NH3 and CrCl3 . 4NH3.
|
Anirban Banerjee answered • Dec 24, 2024 JEE |
Sum of number of ions in aqueous solution of CrCl3.5NH3 and CrCl3
CrCl3.5NH3
CrCl3.5NH3 is a complex compound consisting of chromium(III) chloride and ammonia. The formula indicates that there are 3 chloride ions (Cl-) and 5 ammonia molecules (NH3) present in the compound.
CrCl3
CrCl3 is a simple ionic compound consisting of chromium(III) chlori... more
CrCl3.5NH3
CrCl3.5NH3 is a complex compound consisting of chromium(III) chloride and ammonia. The formula indicates that there are 3 chloride ions (Cl-) and 5 ammonia molecules (NH3) present in the compound.
CrCl3
CrCl3 is a simple ionic compound consisting of chromium(III) chlori... more
- a)2 - √3
- b)2 + √3
- c)16 - √3
- d)14 - √3
- e)None of these
Correct answer is option 'C'. Can you explain this answer?
a)
2 - √3
b)
2 + √3
c)
16 - √3
d)
14 - √3
e)
None of these
|
Knowledge Center answered • Aug 09, 2024 JEE |
Given expression:
[(2 + √3) / (2 - √3)] + [(2 - √3) / (2 + √3)] + [(√3 - 1) / (√3 + 1)]
- Simplify the first two terms:
- The denominator simplifies to 1.
- The numerator becomes 14.
- Result: 14.
- Simplify the third term:
- Rationalize the denominator to get 2 - √3.
- Add the results:
- 14 + (2 - √3) = 14 - √3.
Correct Answer: C: 14 - √3
The annual income of Victor and Angela are in the ratio 8 : 3 and their annual expenditures are in the ratio 4 : 1. If each save Rs. 2000 per annum. What is the annual expense of Angela?a)2000b)4000c)5000d)2500Correct answer is option 'D'. Can you explain this answer?
|
Aarav Sharma answered • Jul 03, 2020 JEE |
: y : z will still be the same as the original ratio.
Let the original ratio be a:b:c, so we can write:
x = a/(a+b+c) * 5000
y = b/(a+b+c) * 5000
z = c/(a+b+c) * 5000
Now, let's apply the given reductions:
x' = (a-50)/(a+b+c) * 5000
y' = (b-100)/(a+b+c) * 5000
z' = (c-150)/(a+b+c) * 5000
We want to show that:
x'/... more
Let the original ratio be a:b:c, so we can write:
x = a/(a+b+c) * 5000
y = b/(a+b+c) * 5000
z = c/(a+b+c) * 5000
Now, let's apply the given reductions:
x' = (a-50)/(a+b+c) * 5000
y' = (b-100)/(a+b+c) * 5000
z' = (c-150)/(a+b+c) * 5000
We want to show that:
x'/... more
Direction: Study the following question carefully and choose the right answer.If ACNE can be coded as 3, 7, 29, 11 then BOIL will be coded as ….?- a)5, 29, 19, 27
- b)5, 29, 19, 25
- c)5, 31, 21, 25
- d)5, 31, 19, 25
Correct answer is option 'D'. Can you explain this answer?
Direction: Study the following question carefully and choose the right answer.
If ACNE can be coded as 3, 7, 29, 11 then BOIL will be coded as ….?
a)
5, 29, 19, 27
b)
5, 29, 19, 25
c)
5, 31, 21, 25
d)
5, 31, 19, 25
|
|
EduRev GATE answered • May 02, 2024 JEE |
In the given coding system, we have:
So, the code for BOIL is 5, 31, 19, 25.
Hence, option D is correct.
So, the code for BOIL is 5, 31, 19, 25.
Hence, option D is correct.
Sailesh is working as a sales executive with a reputed FMCG Company in Hyderabad. As per the Company’s policy, Sailesh gets a commission of 6% on all sales upto Rs. 1,00,000 and 5% on all sales in excess of this amount. If Sailesh remits Rs. 2,65,000 to the FMCG company after deducting his commission, his total sales were worth:- a)Rs. 2,80,000
- b)Rs. 2,90,526
- c)Rs. 2,21,054
- d)Rs. 1,20,000
Correct answer is option 'A'. Can you explain this answer?
Sailesh is working as a sales executive with a reputed FMCG Company in Hyderabad. As per the Company’s policy, Sailesh gets a commission of 6% on all sales upto Rs. 1,00,000 and 5% on all sales in excess of this amount. If Sailesh remits Rs. 2,65,000 to the FMCG company after deducting his commission, his total sales were worth:
a)
Rs. 2,80,000
b)
Rs. 2,90,526
c)
Rs. 2,21,054
d)
Rs. 1,20,000
|
EduRev CLAT answered • Aug 20, 2024 JEE |
Let total sales be ‘x’
The commission that Sailesh will get is x – 265000
He gets 6% on sales upto 100000 and 5% on sales greater than that.
Calculating his commission on total sales:
0.06*100000 + 0.05(x-100000)
Equating,
0.05x + 1000 = x – 265000
0.95x = 266000
x= 280000
Hence, his sales were worth 280,000
Mayank can do 50% more work than Shishu in the same time. Shishu alone can do a piece of work in 30 hours. Shishu starts working and he had already worked for 12 hours when Mayank joins him. How many hours should Shishu and Mayank work together to complete the remaining work?- a)6
- b)12
- c)4.8
- d)7.2
Correct answer is option 'D'. Can you explain this answer?
Mayank can do 50% more work than Shishu in the same time. Shishu alone can do a piece of work in 30 hours. Shishu starts working and he had already worked for 12 hours when Mayank joins him. How many hours should Shishu and Mayank work together to complete the remaining work?
a)
6
b)
12
c)
4.8
d)
7.2
|
Ishani Rane answered • Apr 03, 2023 JEE |
Shishu alone does the work in 30 hours
So in 1 hour he does 1/30 of the work
Mayank in 1 hour does 1/30 + 1/2*1/30= 1/30 +1/60 = 3/60 = 1/20 of the work
Together in 1 hour they do 1/30 +1/20 = 5/60 = 1/12 of the work
Together they can finish the work in 12 hours
Shishu in 12 hours does 12/ 30 = 2/5
Remaining work = 3/5
3/5 X 12 = 36/5 = 7.2 hours
What would be the horse power of a steam engine with average pressure of steam 9x 104 Nm-2 , the area of cross section of the piston is 0.2 m2, length of stroke is 0.6 m and piston makes 5 revolutions per second?- a)150 h.p.
- b)140.7 h.p.
- c)104.7 h.p.
- d)144.77 h.p.
Correct answer is option 'D'. Can you explain this answer?
What would be the horse power of a steam engine with average pressure of steam 9x 104 Nm-2 , the area of cross section of the piston is 0.2 m2, length of stroke is 0.6 m and piston makes 5 revolutions per second?
a)
150 h.p.
b)
140.7 h.p.
c)
104.7 h.p.
d)
144.77 h.p.
|
Arnav Chawla answered • Aug 24, 2021 JEE |
To calculate the horsepower of a steam engine, we need to use the formula:
Horsepower = (Force x Distance) / Time
First, we need to calculate the force exerted by the steam on the piston. The force can be determined using the formula:
Force = Pressure x Area
Given that the average pressure of the steam is 9 x 10^4 N/m^2 and the area of the cross-section ... more
Horsepower = (Force x Distance) / Time
First, we need to calculate the force exerted by the steam on the piston. The force can be determined using the formula:
Force = Pressure x Area
Given that the average pressure of the steam is 9 x 10^4 N/m^2 and the area of the cross-section ... more
What will be at the sign of interrogation?
- a)10
- b)13
- c)12
- d)11
Correct answer is option 'B'. Can you explain this answer?
What will be at the sign of interrogation?
a)
10
b)
13
c)
12
d)
11
|
|
Anjali Sharma answered • Jun 03, 2025 JEE |
According to the given figure:
The numbers in the triangle adjacent to the rectangular block, when added to thrice the number which is adjacent to that particular triangle in the anticlockwise direction, will result in the number in the rectangular block:
⇒ 1 + 4 × 3 = 13
⇒ 2 + 1 × 3 = 5
⇒ 3 + 2 × 3 = 9
Let us consider the unknown number to be x. By applying the above pattern, we get:
⇒ x = 4 + 3 × 3 = 13
⇒ x = 13
Hence, the correct answer is 13.
The numbers in the triangle adjacent to the rectangular block, when added to thrice the number which is adjacent to that particular triangle in the anticlockwise direction, will result in the number in the rectangular block:
⇒ 1 + 4 × 3 = 13
⇒ 2 + 1 × 3 = 5
⇒ 3 + 2 × 3 = 9
Let us consider the unknown number to be x. By applying the above pattern, we get:
⇒ x = 4 + 3 × 3 = 13
⇒ x = 13
Hence, the correct answer is 13.
The displacement of a particle is given by x = (t – 2)2 where x is in meters and t in seconds. The distance covered by the particle in the first 4 seconds is:
- a)4 m
- b)12 m
- c)16 m
- d) 8 m
Correct answer is option 'D'. Can you explain this answer?
The displacement of a particle is given by x = (t – 2)2 where x is in meters and t in seconds. The distance covered by the particle in the first 4 seconds is:
a)
4 m
b)
12 m
c)
16 m
d)
8 m
|
Ananya Sarkar answered • Apr 06, 2020 JEE |
The rest of the question is missing. Please provide complete information.
In a group of people, 28% of the members are young while the rest are old. If 65% of the members are literates, and 25% of the literates are young, then the percentage of old people among the illiterates is nearest to
- a)62
- b)55
- c)66
- d)59
Correct answer is option 'C'. Can you explain this answer?
In a group of people, 28% of the members are young while the rest are old. If 65% of the members are literates, and 25% of the literates are young, then the percentage of old people among the illiterates is nearest to
a)
62
b)
55
c)
66
d)
59
|
S.S Career Academy answered • 3 weeks ago JEE |
Let ‘x’ be the strength of group G. Based on the information, 0.65x constitutes of literate people {the rest 0.35x = illiterate}
Of this 0.65x , 75% are old people =(0.75)0.65x old literates.
The total number of old people in group G is 0.72x {72% of the total}.
Thus, the total number of old people who are illiterate = 0.72x - 0.4875x = 0.2325x.
This is
≈ 66& of the total number of illiterates.
Hence, Option C is the correct answer.
Of this 0.65x , 75% are old people =(0.75)0.65x old literates.
The total number of old people in group G is 0.72x {72% of the total}.
Thus, the total number of old people who are illiterate = 0.72x - 0.4875x = 0.2325x.
This is
≈ 66& of the total number of illiterates.
Hence, Option C is the correct answer.
Two plates are oppositely charged uniformly and kept parallel to each other at a certain distance. What will be the nature of electric field lines in between them?- a)Circular
- b)Parallel to each other throughout the cross section
- c)Not uniformly distributed
- d)Parallel and uniform in central part but fringes out at the extreme ends
Correct answer is option 'D'. Can you explain this answer?
Two plates are oppositely charged uniformly and kept parallel to each other at a certain distance. What will be the nature of electric field lines in between them?
a)
Circular
b)
Parallel to each other throughout the cross section
c)
Not uniformly distributed
d)
Parallel and uniform in central part but fringes out at the extreme ends
|
Keerthana Iyer answered • 4 weeks ago JEE |
Electric Field Lines between Parallel Plates
When two plates are oppositely charged and kept parallel to each other at a certain distance, an electric field is established between them. The nature of electric field lines in between them is as follows:
Uniform Electric Field in Central Part
In the central part of the space between the plates, the electric field line... more
When two plates are oppositely charged and kept parallel to each other at a certain distance, an electric field is established between them. The nature of electric field lines in between them is as follows:
Uniform Electric Field in Central Part
In the central part of the space between the plates, the electric field line... more
- a)51
- b)59
- c)57
- d)53
- e)None of these
Correct answer is option 'C'. Can you explain this answer?
a)
51
b)
59
c)
57
d)
53
e)
None of these
|
|
Knowledge Center answered • Jun 18, 2024 JEE |
Solution for ∛185193
To solve ∛185193, we find the cube root:
- The cube root of 185193 is 57, since 57³ = 185193.
Correct Answer: C: 57
The voltage 7.25 sin (300t) is applied to a series RLC circuit with R = 120 ohms, L = 0.140 H and C = 1.45 μF. What is the impedance Z and the phase angle θ?- a)120 ohms, -10.2o
- b)306 ohms, -68.1o
- c)2340 ohms, -25.7o
- d)2260 ohms, -87o
Correct answer is option 'D'. Can you explain this answer?
The voltage 7.25 sin (300t) is applied to a series RLC circuit with R = 120 ohms, L = 0.140 H and C = 1.45 μF. What is the impedance Z and the phase angle θ?
a)
120 ohms, -10.2o
b)
306 ohms, -68.1o
c)
2340 ohms, -25.7o
d)
2260 ohms, -87o
|
Naina Kumar answered • May 20, 2024 JEE |
Calculating Impedance and Phase Angle:
Given data:
- Voltage: V = 7.25 sin(300t) V
- R = 120 ohms
- L = 0.140 H
- C = 1.45 μF
Impedance (Z) Formula:
- Impedance in an RLC circuit is given by the formula:
Z = √(R^2 + (XL - XC)^2)
where XL = 2πfL and XC = 1/(2πfC)
Calculations:
- XL = 2πfL = 2π*300*0... more
Given data:
- Voltage: V = 7.25 sin(300t) V
- R = 120 ohms
- L = 0.140 H
- C = 1.45 μF
Impedance (Z) Formula:
- Impedance in an RLC circuit is given by the formula:
Z = √(R^2 + (XL - XC)^2)
where XL = 2πfL and XC = 1/(2πfC)
Calculations:
- XL = 2πfL = 2π*300*0... more
The electric intensity due to a dipole of length10 cm and having a charge of 500 μC, at a pointon the axis at a distance 20 cm from one of thecharges in air, is [2001]- a)6.25 × 107 N/C
- b)9.28 × 107 N/C
- c)13.1 × 1011 N/C
- d)20.5 × 107 N/C
Correct answer is option 'A'. Can you explain this answer?
The electric intensity due to a dipole of length10 cm and having a charge of 500 μC, at a pointon the axis at a distance 20 cm from one of thecharges in air, is [2001]
a)
6.25 × 107 N/C
b)
9.28 × 107 N/C
c)
13.1 × 1011 N/C
d)
20.5 × 107 N/C
|
Sonal Kulkarni answered • Jun 04, 2025 JEE |
Given : Length of the dipole (2l) =10cm
= 0.1m or l = 0.05 m
Charge on the dipole (q) = 500 μC = 500 ×
10–6 C and distance of the point on the axis
from the mid-point of the dipole (r) = 20 + 5 =
25 cm = 0.25 m. We know that the electric
field intensity due to dipole on the given
= 0.1m or l = 0.05 m
Charge on the dipole (q) = 500 μC = 500 ×
10–6 C and distance of the point on the axis
from the mid-point of the dipole (r) = 20 + 5 =
25 cm = 0.25 m. We know that the electric
field intensity due to dipole on the given
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