All India Computer Science Engineering (CSE) Group

Suppose we have a balanced binary search tree T holding n numbers. We are given two numbers L and H and wish to sum up all the numbers in T that lie between L and H. Suppose there are m such numbers in T. If the tightest upper bound on the time to compute the sum is O(nalogb n + mclogd n), the value of a + 10b + 100c + 1000d is ____.
  • a)
    60
  • b)
    110
  • c)
    210
  • d)
    50
Correct answer is option 'B'. Can you explain this answer?

Anoushka Dey answered  •  yesterday
Understanding the Problem
The challenge is to sum all numbers in a balanced binary search tree (BST) that fall within a specified range [L, H]. We know that:
- T holds n numbers.
- There are m numbers in T that lie between L and H.
Time Complexity Explanation
The time complexity for this operation is given as O(nalogbn + mclogdn). Here’s how to interpret each
... more

Example 1:
Consider array has 4 elements and a searching element 16.
A[4]= {10, 16, 22, 25} 
The number of iterations are required to search an element by using a binary search= T1
Example 2:
Consider array has 4 elements and a searching element 22.
A[4]= {10, 16, 22, 25} 
The number of iterations are required to search an element by using a binary search= T2
Note: Searching is successful.
Q.Which of the following statement are true?
  • a)
    T1 = T2
  • b)
    T1 < T2
  • c)
    T1 >T2
  • d)
    T2 < T1
Correct answer is option 'B'. Can you explain this answer?

Sankar Sarkar answered  •  2 days ago
Understanding Binary Search Iterations
Binary search is an efficient algorithm used to find an element in a sorted array. The number of iterations required to find an element can vary based on the position of the element being searched.
Example Analysis
- Array Elements: A[4] = {10, 16, 22, 25}
- Searching Element for Example 1: 16
- Searchin
... more: 22
Iteration Details
- T1 (Searching for 16):
- Start with the entire array: indexes 0 to 3.
- Middle index = 1 (value = 16).
- Found in 1 iteration.
- T2 (Searching for 22):
- Start with the entire array: indexes 0 to 3.
- Middle index = 1 (value = 16).
- Since 22 > 16, search the right half (indexes 2 to 3).
- New middle index = 2 (value = 22).
- Found in 2 iterations.
Conclusion
- Comparison of Iterations:
- T1 (1 iteration) is less than T2 (2 iterations).
Thus, the statement T1 < /> is correct, making option b the true statement.
Summary of Options
- a) T1 = T2: False
- b) T1 < t2:="" />
- c) T1 > T2: False
- d) T2 < t1:="" />
Understanding the binary search algorithm's mechanics is crucial in determining how many iterations are needed based on the searched element's position.

In programming languages like C, C++, Python . . . the memory used by a program is typically separated into two parts, the stack and the heap.
Consider the following statements:
1. A stack is efficient for managing nested function calls.
2. Stack space is limited while heap space is not.
3. The stack cannot be used for persistent data structures.
  • a)
    1 and 2 are true but 3 is false.
  • b)
    1 and 3 are true but 2 is false.
  • c)
    2 and 3 are true but 1 is false.
  • d)
    All three statements are true.
Correct answer is option 'B'. Can you explain this answer?

Arka Shah answered  •  3 days ago
Understanding Stack and Heap Memory
In programming, memory management is crucial for efficient execution. The stack and heap serve different purposes, leading to the evaluation of the statements provided.
Statement 1: A stack is efficient for managing nested function calls.
- This statement is true.
- The stack operates in a Last In, First Out (LIFO) manne
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Jyoti Nair asked a question

Each of the 10 persons namely A, Q, R, Z, M, N, P, B, K and L are wearing a shirt. The colour of each shirt is one out of blue, green and red. There are ten chairs placed in a row. The chairs are consecutively numbered 1, 2, 3, 4...9 and 10 from left to right in that order. These ten persons have to sit on the chairs such that there is only one person in each chair. The number of persons wearing a green and a blue shirt is 2 and 3 respectively.
Additional Information:
1. No two persons wearing blue shirts sit on consecutively numbered chairs.
2. Among the persons wearing red shirts, exactly three persons always are sitting together while the remaining two never.
3. A person wearing a blue shirt and a person wearing a green shirt never is sitting on consecutively numbered chairs.
4. A person wearing a green shirt cannot sit on chairs numbered 2 or 9.
5. Persons wearing red shirts are not sitting at extreme ends.
The following table provides information about the six different seating arrangements namely I, II, III, IV, V and VI of the ten persons done by Mr. Crazy. He observed that out of all the seating arrangements done by him, there is one arrangement that is not consistent with the information stated under "Additional Information".
Q. Which of the arrangements done by Mr. Crazy is not consistent with the information stated under "Additional Information"?
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