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A slide wire potentiometer is used to measure voltage across a dc circuit. The voltage is 1.2V as read by the potentiometer. Across the same points 20000 W/V voltmeter reads 0.6V on its 5V range. Input resistance between the two point is
  • a)
    20000 W
  • b)
    100,000 W
  • c)
    50000 W
  • d)
    120,000 W
Correct answer is option 'B'. Can you explain this answer?
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Explanation:

  • A slide wire potentiometer is used to measure voltage across a dc circuit.

  • The voltage measured by the potentiometer is 1.2V.

  • A 20000 W/V voltmeter reads 0.6V on its 5V range across the same points.

  • The input resistance between the two points can be calculated using the formula: R = V/I where R is the resistance, V is the voltage and I is the current.

  • For the potentiometer, the current flowing through it is very small and can be considered negligible.

  • Therefore, the input resistance for the potentiometer is R = V/I = 1.2V/0A = infinity (open circuit).

  • For the voltmeter, the current flowing through it is I = V/R = 0.6V/20000W/V = 0.00003A.

  • The input resistance for the voltmeter is R = V/I = 5V/0.00003A = 166666.67 W.

  • However, the voltmeter range used was 5V, which means that the voltmeter has an internal resistance of 5V/0.00003A = 166666.67 W.

  • Therefore, the input resistance between the two points is the difference between the input resistance of the voltmeter and the potentiometer, which is 166666.67 W - infinity = 100,000 W.

  • Hence, the correct answer is option 'B'.

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A slide wire potentiometer is used to measure voltage across a dc circuit. The voltage is 1.2V as read by the potentiometer. Across the same points 20000 W/V voltmeter reads 0.6V on its 5V range. Input resistance between the two point isa)20000 Wb)100,000 Wc)50000 Wd)120,000 WCorrect answer is option 'B'. Can you explain this answer?
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