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If alpha and beta are the zeroes of the polynomial f(x)=x^2-3x 6, then find the value of 1/alpha 1/beta alpha^2 beta^2 -2 ×alpha×beta?
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If alpha and beta are the zeroes of the polynomial f(x)=x^2-3x 6, then...
Given:
The polynomial f(x) = x^2 - 3x + 6 has zeroes alpha and beta.

To find:
The value of (1/alpha) * (1/beta) * (alpha^2) * (beta^2) - 2 * alpha * beta.

Solution:
Step 1: Find the sum and product of the zeroes:
The sum of the zeroes is given by the formula: alpha + beta = -(-3) = 3.
The product of the zeroes is given by the formula: alpha * beta = 6.

Step 2: Find the value of (alpha^2) * (beta^2):
Using the identity (alpha + beta)^2 = (alpha^2) + 2 * alpha * beta + (beta^2), we can rewrite it as:
(3)^2 = (alpha^2) + 2 * alpha * beta + (beta^2).

Simplifying the equation:
9 = (alpha^2) + 2 * alpha * beta + (beta^2).

Substituting the value of (alpha * beta) from Step 1:
9 = (alpha^2) + 2 * 6 + (beta^2).
9 = (alpha^2) + 12 + (beta^2).

Rearranging the equation:
(alpha^2) + (beta^2) = 9 - 12.
(alpha^2) + (beta^2) = -3.

Step 3: Substitute the values in the given expression:
(1/alpha) * (1/beta) * (alpha^2) * (beta^2) - 2 * alpha * beta
= (1/alpha) * (1/beta) * (-3) - 2 * alpha * beta.

Simplifying the expression:
= (-3/alpha * beta) - 2 * alpha * beta.

Substituting the value of (alpha * beta) from Step 1:
= (-3/6) - 2 * 6.
= -1/2 - 12.
= -1/2 - 24/2.
= -25/2.

Final Answer:
The value of (1/alpha) * (1/beta) * (alpha^2) * (beta^2) - 2 * alpha * beta is -25/2.
Community Answer
If alpha and beta are the zeroes of the polynomial f(x)=x^2-3x 6, then...
Can u please correct the question
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