Class 11 Exam > Class 11 Questions > From an elevated point P, a stone is projecte...
Start Learning for Free
From an elevated point P, a stone is projected vertically upwards. When the stone reaches a distance h below P.,its velocity is double of its velocity at a height h above P. The greatest height attained by the stone from the point of projection P is?
Most Upvoted Answer
From an elevated point P, a stone is projected vertically upwards. Whe...
Community Answer
From an elevated point P, a stone is projected vertically upwards. Whe...
Problem:
From an elevated point P, a stone is projected vertically upwards. When the stone reaches a distance h below P, its velocity is double of its velocity at a height h above P. The greatest height attained by the stone from the point of projection P is?
Solution:
Let's assume that the initial velocity of the stone is u and it reaches a maximum height of h1 before starting to fall back down. The velocity of the stone at height h above P can be calculated using the formula:
v1^2 = u^2 - 2gh
where g is the acceleration due to gravity.
When the stone reaches a distance h below P, its velocity can be calculated using the same formula:
v2^2 = u^2 + 2gh
Since we know that the velocity at h is double of the velocity at h1, we can write:
2v1^2 = v2^2
Substituting the values of v1^2 and v2^2 in the above equation, we get:
2(u^2 - 2gh)^2 = (u^2 + 2gh)^2
Simplifying the above equation, we get:
h = u^2/8g
This means that the maximum height attained by the stone is directly proportional to the square of the initial velocity and inversely proportional to the acceleration due to gravity.
Therefore, the greatest height attained by the stone from the point of projection P is h1 + h, which is equal to:
h1 + u^2/8g
Conclusion:
The maximum height attained by the stone can be calculated using the formula h1 + u^2/8g, where h1 is the maximum height reached before starting to fall back down, u is the initial velocity of the stone and g is the acceleration due to gravity.
From an elevated point P, a stone is projected vertically upwards. When the stone reaches a distance h below P, its velocity is double of its velocity at a height h above P. The greatest height attained by the stone from the point of projection P is?
Solution:
Let's assume that the initial velocity of the stone is u and it reaches a maximum height of h1 before starting to fall back down. The velocity of the stone at height h above P can be calculated using the formula:
v1^2 = u^2 - 2gh
where g is the acceleration due to gravity.
When the stone reaches a distance h below P, its velocity can be calculated using the same formula:
v2^2 = u^2 + 2gh
Since we know that the velocity at h is double of the velocity at h1, we can write:
2v1^2 = v2^2
Substituting the values of v1^2 and v2^2 in the above equation, we get:
2(u^2 - 2gh)^2 = (u^2 + 2gh)^2
Simplifying the above equation, we get:
h = u^2/8g
This means that the maximum height attained by the stone is directly proportional to the square of the initial velocity and inversely proportional to the acceleration due to gravity.
Therefore, the greatest height attained by the stone from the point of projection P is h1 + h, which is equal to:
h1 + u^2/8g
Conclusion:
The maximum height attained by the stone can be calculated using the formula h1 + u^2/8g, where h1 is the maximum height reached before starting to fall back down, u is the initial velocity of the stone and g is the acceleration due to gravity.
Attention Class 11 Students!
To make sure you are not studying endlessly, EduRev has designed Class 11 study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Class 11.
|
Explore Courses for Class 11 exam
|
|
Similar Class 11 Doubts
Top Courses for Class 11View all
From an elevated point P, a stone is projected vertically upwards. When the stone reaches a distance h below P.,its velocity is double of its velocity at a height h above P. The greatest height attained by the stone from the point of projection P is?
Question Description
From an elevated point P, a stone is projected vertically upwards. When the stone reaches a distance h below P.,its velocity is double of its velocity at a height h above P. The greatest height attained by the stone from the point of projection P is? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about From an elevated point P, a stone is projected vertically upwards. When the stone reaches a distance h below P.,its velocity is double of its velocity at a height h above P. The greatest height attained by the stone from the point of projection P is? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for From an elevated point P, a stone is projected vertically upwards. When the stone reaches a distance h below P.,its velocity is double of its velocity at a height h above P. The greatest height attained by the stone from the point of projection P is?.
From an elevated point P, a stone is projected vertically upwards. When the stone reaches a distance h below P.,its velocity is double of its velocity at a height h above P. The greatest height attained by the stone from the point of projection P is? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about From an elevated point P, a stone is projected vertically upwards. When the stone reaches a distance h below P.,its velocity is double of its velocity at a height h above P. The greatest height attained by the stone from the point of projection P is? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for From an elevated point P, a stone is projected vertically upwards. When the stone reaches a distance h below P.,its velocity is double of its velocity at a height h above P. The greatest height attained by the stone from the point of projection P is?.
Solutions for From an elevated point P, a stone is projected vertically upwards. When the stone reaches a distance h below P.,its velocity is double of its velocity at a height h above P. The greatest height attained by the stone from the point of projection P is? in English & in Hindi are available as part of our courses for Class 11.
Download more important topics, notes, lectures and mock test series for Class 11 Exam by signing up for free.
Here you can find the meaning of From an elevated point P, a stone is projected vertically upwards. When the stone reaches a distance h below P.,its velocity is double of its velocity at a height h above P. The greatest height attained by the stone from the point of projection P is? defined & explained in the simplest way possible. Besides giving the explanation of
From an elevated point P, a stone is projected vertically upwards. When the stone reaches a distance h below P.,its velocity is double of its velocity at a height h above P. The greatest height attained by the stone from the point of projection P is?, a detailed solution for From an elevated point P, a stone is projected vertically upwards. When the stone reaches a distance h below P.,its velocity is double of its velocity at a height h above P. The greatest height attained by the stone from the point of projection P is? has been provided alongside types of From an elevated point P, a stone is projected vertically upwards. When the stone reaches a distance h below P.,its velocity is double of its velocity at a height h above P. The greatest height attained by the stone from the point of projection P is? theory, EduRev gives you an
ample number of questions to practice From an elevated point P, a stone is projected vertically upwards. When the stone reaches a distance h below P.,its velocity is double of its velocity at a height h above P. The greatest height attained by the stone from the point of projection P is? tests, examples and also practice Class 11 tests.
|
|
Explore Courses for Class 11 exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup