A 100 ohm resistance and a capacitor of 100ohm reactance are connected...
Understanding the Circuit
In this circuit, a 100-ohm resistor and a capacitor with 100-ohm reactance are connected in series across a 220V AC source. To find the peak value of the displacement current, we need to analyze the circuit's impedance and current flow.
Impedance Calculation
- The impedance (Z) of the circuit can be calculated using the formula:
Z = √(R² + Xc²)
- Here, R = 100 ohms and Xc = 100 ohms.
- Thus, Z = √(100² + 100²) = √(20000) = 141.42 ohms.
RMS Voltage and Current Calculation
- The RMS value of the voltage (V) is given as 220V.
- The RMS current (I) can be calculated using Ohm's law:
I = V / Z
- Therefore, I = 220V / 141.42 ohms = 1.55 A (approximately).
Peak Current Calculation
- The peak current (Ip) is related to the RMS current (I) by the formula:
Ip = I × √2
- Therefore, Ip = 1.55 A × √2 = 2.2 A (approximately).
Final Answer
- The peak value of the displacement current is C) 2.2 A.
This analysis highlights the relationship between resistance, reactance, and current in an AC circuit, leading us to the correct answer through systematic calculations.
A 100 ohm resistance and a capacitor of 100ohm reactance are connected...
C)