**Solution:**

To find the value of tanA cotA, we first need to determine the value of tanA and cotA separately.

Given: sinA cosA = √3

We know that sinA cosA = (1/2) * 2 * sinA * cosA
Using the identity sin2A = (1/2) * (1 - cos2A), we can rewrite the equation as:

(1/2) * 2 * sinA * cosA = (1/2) * (1 - cos2A)
sinA * cosA = (1/2) * (1 - cos2A)
sinA * cosA = (1/2) - (1/2) * cos2A

Now, let's solve for cos2A using the identity sin2A + cos2A = 1:

sin2A + cos2A = 1
cos2A = 1 - sin2A

Substituting this value into the previous equation:

sinA * cosA = (1/2) - (1/2) * (1 - sin2A)
sinA * cosA = (1/2) - (1/2) + (1/2) * sin2A
sinA * cosA = (1/2) * sin2A

Now, we can square both sides of the equation to eliminate the square root:

(sinA * cosA)2 = (√3)2
sin2A * cos2A = 3

Substituting the value of cos2A from the earlier identity:

sin2A * (1 - sin2A) = 3
sin2A - sin4A = 3

Let's solve this quadratic equation:

sin4A - sin2A + 3 = 0

Now, we can solve this equation to find the value of sinA. Once we have sinA, we can calculate cosA using the identity cos2A = 1 - sin2A.

Once we have both sinA and cosA, we can find the values of tanA and cotA using the following identities:

tanA = sinA / cosA
cotA = 1 / tanA

Finally, we can substitute the values of sinA and cosA into these equations to find the value of tanA cotA.

Please note that the solution to the quadratic equation may require the use of a calculator or other mathematical methods.

sinA+cosA=√3p/h+b/h=√3p+b=√3hon squaring both sidep^2+b^2+2pb=3h^2h^2+2pb=3h^2. {p^2+b^2=h^2}2pb=2h^2pb=h^2. -1tanA+cotA=p/b+b/p =p^2+b^2/bp =h^2/bp. {p^2+b^2=h^2} =1. {by eq. 1}