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If an angle A of a ΔABC satisfies  5 cosA + 3 = 0, then the roots of the quadratic equaiton, 9x2 + 27x + 20 = 0 are :
  • a)
    sec A, cotA
  • b)
    secA, tanA
  • c)
    tanA, cosA
  • d)
    sinA, secA
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
If an angle A of a ΔABC satisfies 5 cosA + 3 = 0, then the roots...
5cosA + 3 = 0 ⇒ cosA = - 3/5 clearly A ∈ (90º, 180º)
Now roots of equation  9x2 + 27x + 20 = 0 are -5/3 and -4/3
⇒ Roots secA and tanA 
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If an angle A of a ΔABC satisfies 5 cosA + 3 = 0, then the roots...
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If an angle A of a ΔABC satisfies 5 cosA + 3 = 0, then the roots...
5cosA + 3 = 0 ⇒ cosA = - 3/5 clearly A ∈ (90º, 180º)
Now roots of equation  9x2 + 27x + 20 = 0 are -5/3 and -4/3
⇒ Roots secA and tanA 
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If an angle A of a ΔABC satisfies 5 cosA + 3 = 0, then the roots of the quadratic equaiton, 9x2 + 27x + 20 = 0 are :a)sec A, cotAb)secA, tanAc)tanA, cosAd)sinA, secACorrect answer is option 'B'. Can you explain this answer?
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If an angle A of a ΔABC satisfies 5 cosA + 3 = 0, then the roots of the quadratic equaiton, 9x2 + 27x + 20 = 0 are :a)sec A, cotAb)secA, tanAc)tanA, cosAd)sinA, secACorrect answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about If an angle A of a ΔABC satisfies 5 cosA + 3 = 0, then the roots of the quadratic equaiton, 9x2 + 27x + 20 = 0 are :a)sec A, cotAb)secA, tanAc)tanA, cosAd)sinA, secACorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If an angle A of a ΔABC satisfies 5 cosA + 3 = 0, then the roots of the quadratic equaiton, 9x2 + 27x + 20 = 0 are :a)sec A, cotAb)secA, tanAc)tanA, cosAd)sinA, secACorrect answer is option 'B'. Can you explain this answer?.
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