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Parallel plate capacitance made with two square plates of 400mm side. the 14 mm space between the plates is filled with two layers of dielectrics of Er=4,6mm thick and Er=2,8mm thick . neglecting fringing of fields at the edge the capacitence is?
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Parallel plate capacitance made with two square plates of 400mm side. ...
Calculation of Parallel Plate Capacitance with Dielectrics
1. Given Parameters:
- Side length of square plates, a = 400 mm
- Distance between plates, d = 14 mm
- Dielectric constant of first layer, εr1 = 4
- Thickness of first dielectric layer, t1 = 6 mm
- Dielectric constant of second layer, εr2 = 2
- Thickness of second dielectric layer, t2 = 8 mm
2. Calculation of Capacitance with Dielectrics:
- Capacitance of a parallel plate capacitor with dielectrics can be calculated using the formula:
C = (ε0 * εr * A) / d
where:
C = capacitance
ε0 = permittivity of free space = 8.85 x 10^-12 F/m
εr = relative permittivity of the dielectric material
A = area of the plates = a^2
d = distance between plates
3. Calculation for First Dielectric Layer:
- Area A1 = a^2 = (400 mm)^2 = 160,000 mm^2
- Capacitance C1 = (ε0 * εr1 * A1) / t1 = (8.85 x 10^-12 * 4 * 160,000) / 6 x 10^-3 = 94.4 pF
4. Calculation for Second Dielectric Layer:
- Area A2 = a^2 = 160,000 mm^2
- Capacitance C2 = (ε0 * εr2 * A2) / t2 = (8.85 x 10^-12 * 2 * 160,000) / 8 x 10^-3 = 35.4 pF
5. Combined Capacitance:
- The capacitance of the two dielectric layers in series is given by:
1 / C = 1 / C1 + 1 / C2
1 / C = 1 / 94.4 + 1 / 35.4
C = 23.8 pF
Therefore, the capacitance of the parallel plate capacitor with the two dielectric layers is 23.8 pF.
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Parallel plate capacitance made with two square plates of 400mm side. the 14 mm space between the plates is filled with two layers of dielectrics of Er=4,6mm thick and Er=2,8mm thick . neglecting fringing of fields at the edge the capacitence is?
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Parallel plate capacitance made with two square plates of 400mm side. the 14 mm space between the plates is filled with two layers of dielectrics of Er=4,6mm thick and Er=2,8mm thick . neglecting fringing of fields at the edge the capacitence is? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about Parallel plate capacitance made with two square plates of 400mm side. the 14 mm space between the plates is filled with two layers of dielectrics of Er=4,6mm thick and Er=2,8mm thick . neglecting fringing of fields at the edge the capacitence is? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Parallel plate capacitance made with two square plates of 400mm side. the 14 mm space between the plates is filled with two layers of dielectrics of Er=4,6mm thick and Er=2,8mm thick . neglecting fringing of fields at the edge the capacitence is?.
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