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One mole of N2H4 loses ten moles of electrons to form a new compound Y. Assuming that all the nitrogen appears in the new compound, what is the oxidation state of nitrogen in Y? (There is no change in the oxidation state of hydrogen). (1981 - 1 Mark)
  • a)
    –1
  • b)
    –3
  • c)
    +3
  • d)
    +5
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
One mole of N2H4 loses ten moles of electrons to form a new compound Y...
TIPS/Formulae : (i) Find oxidation state of N in N2H4.
(ii) Find change in oxidation number with the help of number of electrons given out during formation of compound Y.
N2H4 → Y + 10 e, Calculation of O.S. of N in
N2H4 : 2x + 4 = 0  ⇒  x = –2 The two nitrogen atoms will balance the charge of 10 e.
Hence oxidation state of N will increase by +5, i.e. from –2 to +3.
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One mole of N2H4 loses ten moles of electrons to form a new compound Y. Assuming that all the nitrogen appears in the new compound, what is the oxidation state of nitrogen in Y? (There is no change in the oxidation state of hydrogen). (1981 - 1 Mark)a)–1b)–3c)+3d)+5Correct answer is option 'C'. Can you explain this answer?
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