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ABC is right-angled at A. ADis perpendicular to BC,AB=5cm,BC=13cm and AC=12cm.Find the area of ABC. Also, Find the length of AD
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ABC is right-angled at A. ADis perpendicular to BC,AB=5cm,BC=13cm and ...
∆ABC is right - angled at A.
so, BC is definitely hypotenuse.
let AB is base and AC is altitude of ∆ABC.
given, AB = 5cm , BC = 13cm and AC = 12cm
now, area of triangle ∆ABC = 1/2 x base x altitude
= 1/2 x length of AB x length of AC
= 1/2 x 5cm x 12cm = 30 cm^2
hence, area of ∆ABC = 30cm^2
area of ∆ABC = 1/2 x length of AB x length of AC = 1/2 x length of BC x length of AD
=> 5cm x 12cm = 13cm x length of AD
=> 60/13 = length of AD
hence, length of AD = 60/13 cm
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