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Phosphorus forms different halide compounds with halogens. In crystalline state some of them exist as ion pairs.
What is hybridisation of central atom of anionic part of PBr5 in crystalline state.
- a)sp2
- b)sp3
- c)sp
- d)Not applicable
Correct answer is option 'D'. Can you explain this answer?
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Phosphorus forms different halide compounds with halogens. In crystall...
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Phosphorus forms different halide compounds with halogens. In crystall...
Explanation:
In the crystalline state, PBr5 exists as ion pairs. This means that the compound is composed of positively charged cations and negatively charged anions. In the case of PBr5, the central atom is phosphorus (P), and it forms an anionic part.
Hybridization of the central atom:
The hybridization of an atom is determined by the number of regions of electron density around it. This can be calculated using the formula:
Hybridization = (Number of sigma bonds + Number of lone pairs)
In the case of PBr5, the central phosphorus atom is bonded to five bromine atoms (Br) and has no lone pairs. This means that the number of sigma bonds is 5 and the number of lone pairs is 0.
Using the formula, we can calculate the hybridization as follows:
Hybridization = (Number of sigma bonds + Number of lone pairs)
= (5 + 0)
= 5
Since the hybridization is 5, it does not match with any of the given options (sp2, sp3, or sp). Therefore, the correct answer is option 'D' (Not applicable).
Conclusion:
In the crystalline state, PBr5 exists as ion pairs, and the central phosphorus atom does not have a specific hybridization that matches with the given options. Therefore, the correct answer is option 'D' (Not applicable).
In the crystalline state, PBr5 exists as ion pairs. This means that the compound is composed of positively charged cations and negatively charged anions. In the case of PBr5, the central atom is phosphorus (P), and it forms an anionic part.
Hybridization of the central atom:
The hybridization of an atom is determined by the number of regions of electron density around it. This can be calculated using the formula:
Hybridization = (Number of sigma bonds + Number of lone pairs)
In the case of PBr5, the central phosphorus atom is bonded to five bromine atoms (Br) and has no lone pairs. This means that the number of sigma bonds is 5 and the number of lone pairs is 0.
Using the formula, we can calculate the hybridization as follows:
Hybridization = (Number of sigma bonds + Number of lone pairs)
= (5 + 0)
= 5
Since the hybridization is 5, it does not match with any of the given options (sp2, sp3, or sp). Therefore, the correct answer is option 'D' (Not applicable).
Conclusion:
In the crystalline state, PBr5 exists as ion pairs, and the central phosphorus atom does not have a specific hybridization that matches with the given options. Therefore, the correct answer is option 'D' (Not applicable).
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Phosphorus forms different halide compounds with halogens. In crystalline state some of them exist as ion pairs.What is hybridisation of central atom of anionic part of PBr5in crystalline state.a)sp2b)sp3c)spd)Not applicableCorrect answer is option 'D'. Can you explain this answer?
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Phosphorus forms different halide compounds with halogens. In crystalline state some of them exist as ion pairs.What is hybridisation of central atom of anionic part of PBr5in crystalline state.a)sp2b)sp3c)spd)Not applicableCorrect answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Phosphorus forms different halide compounds with halogens. In crystalline state some of them exist as ion pairs.What is hybridisation of central atom of anionic part of PBr5in crystalline state.a)sp2b)sp3c)spd)Not applicableCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Phosphorus forms different halide compounds with halogens. In crystalline state some of them exist as ion pairs.What is hybridisation of central atom of anionic part of PBr5in crystalline state.a)sp2b)sp3c)spd)Not applicableCorrect answer is option 'D'. Can you explain this answer?.
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