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The block of mass M moving on the frictionless horizontal surface collides with the spring of spring constant k and compresses it by length L. The maximum momentum of the block after collision is
[AIEEE 2005]
 
  • a)
     
  • b)
     
  • c)
     zero
  • d)
     
Correct answer is option 'A'. Can you explain this answer?
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As after collision total kinetic energy is converted into spring potential energy                                                                               p^2/2m=kl^2/2  , p=(mk)^1/2l. (opt.A)
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The block of mass M moving on the frictionless horizontal surface collides with the spring of spring constant k and compresses it by length L. The maximum momentum of the block after collision is[AIEEE 2005]a)b)c)zerod)Correct answer is option 'A'. Can you explain this answer?
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