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When a current is passed through water acidified with a dilute sulphuric acid, the gases formed at the platinum electrodes are
- a)2 volume hydrogen (cathode) and one volume oxygen (anode)
- b)1 volume hydrogen (cathode) and one volume oxygen (anode)
- c)1 volume oxygen (cathode) and 2 volume hydrogen (anode)
- d)2 volume oxygen (cathode) and 1 volume hydrogen (anode)
Correct answer is option 'A'. Can you explain this answer?
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When a current is passed through water acidified with a dilute sulphur...
Electrolysis of Water
Electrolysis of water is the decomposition of water into oxygen and hydrogen gas due to the passage of an electric current through the water.
Reaction
The reaction at the anode (positive electrode) during electrolysis is:
2H2O(l) → O2(g) + 4H+(aq) + 4e−
The reaction at the cathode (negative electrode) is:
4H+(aq) + 4e− → 2H2(g)
Explanation
When an electric current is passed through water acidified with dilute sulphuric acid, the water molecule undergoes electrolysis, and the following reaction takes place at the anode and cathode.
At the anode, the water molecule loses electrons and releases oxygen gas.
2H2O → 4H+ + O2 + 4e-
At the cathode, the hydrogen ions gain electrons and form hydrogen gas.
4H+ + 4e- → 2H2
Since the reaction at the cathode forms twice the volume of hydrogen gas than the volume of oxygen gas formed at the anode, the correct answer is option A, which is 2 volumes of hydrogen (cathode) and 1 volume of oxygen (anode).
Electrolysis of water is the decomposition of water into oxygen and hydrogen gas due to the passage of an electric current through the water.
Reaction
The reaction at the anode (positive electrode) during electrolysis is:
2H2O(l) → O2(g) + 4H+(aq) + 4e−
The reaction at the cathode (negative electrode) is:
4H+(aq) + 4e− → 2H2(g)
Explanation
When an electric current is passed through water acidified with dilute sulphuric acid, the water molecule undergoes electrolysis, and the following reaction takes place at the anode and cathode.
At the anode, the water molecule loses electrons and releases oxygen gas.
2H2O → 4H+ + O2 + 4e-
At the cathode, the hydrogen ions gain electrons and form hydrogen gas.
4H+ + 4e- → 2H2
Since the reaction at the cathode forms twice the volume of hydrogen gas than the volume of oxygen gas formed at the anode, the correct answer is option A, which is 2 volumes of hydrogen (cathode) and 1 volume of oxygen (anode).
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When a current is passed through water acidified with a dilute sulphur...
Electrolysis of Water
Electrolysis is the process of decomposing a compound using electricity. When an electric current is passed through a solution of water acidified with dilute sulphuric acid, electrolysis takes place. The positive ions move towards the cathode and the negative ions move towards the anode. At the electrodes, the ions gain or lose electrons and are converted into neutral atoms or molecules.
Gases formed at Platinum Electrodes
At the cathode, hydrogen ions (H+) gain electrons and are converted into hydrogen gas (H2). The hydrogen gas is collected at the cathode.
At the anode, hydroxide ions (OH-) lose electrons and are converted into oxygen gas (O2) and water (H2O). The oxygen gas is collected at the anode.
The overall reaction is:
2H2O(l) → 2H2(g) + O2(g)
Volume of Gases Formed
The volume of hydrogen gas formed at the cathode is twice the volume of oxygen gas formed at the anode. This is because the ratio of the volumes of hydrogen gas to oxygen gas in water is 2:1.
Therefore, the correct option is A: 2 volume hydrogen (cathode) and one volume oxygen (anode).
Electrolysis is the process of decomposing a compound using electricity. When an electric current is passed through a solution of water acidified with dilute sulphuric acid, electrolysis takes place. The positive ions move towards the cathode and the negative ions move towards the anode. At the electrodes, the ions gain or lose electrons and are converted into neutral atoms or molecules.
Gases formed at Platinum Electrodes
At the cathode, hydrogen ions (H+) gain electrons and are converted into hydrogen gas (H2). The hydrogen gas is collected at the cathode.
At the anode, hydroxide ions (OH-) lose electrons and are converted into oxygen gas (O2) and water (H2O). The oxygen gas is collected at the anode.
The overall reaction is:
2H2O(l) → 2H2(g) + O2(g)
Volume of Gases Formed
The volume of hydrogen gas formed at the cathode is twice the volume of oxygen gas formed at the anode. This is because the ratio of the volumes of hydrogen gas to oxygen gas in water is 2:1.
Therefore, the correct option is A: 2 volume hydrogen (cathode) and one volume oxygen (anode).
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