JEE Exam  >  JEE Questions  >  A current of 3amp was passed through nickel s... Start Learning for Free
A current of 3amp was passed through nickel sulphate solution for five hours, using a square strip of platinum of 4 cm side as cathode. The current efficiency is 60% for the deposition of nickel. Then, thevolume of O2 and H2 (if the rest of 40% of current is utilised for hydrogen evolution) released at STP are
(a) 3.13 lit, 2.51 lit
(b) 1.88 lit, 2.51 lit
(c) 3.13 lit, 1.88 lit
(d) 3.13 lit, 6.26 lit?
Most Upvoted Answer
A current of 3amp was passed through nickel sulphate solution for five...
Calculation of Volume of O2 and H2 Released

Given Data:
- Current = 3 A
- Time = 5 hours
- Side of platinum strip = 4 cm
- Current efficiency = 60%

Step 1: Calculate the amount of nickel deposited
- Faraday's constant (F) = 96500 C/mol
- Atomic weight of nickel = 58.7 g/mol
- Charge passed = Current × Time = 3 A × 5 hours = 15 C
- Number of moles of nickel deposited = Charge passed / (2 × F) = 15 / (2 × 96500) = 7.82 × 10^-5 mol
- Mass of nickel deposited = Number of moles × Atomic weight = 7.82 × 10^-5 mol × 58.7 g/mol = 0.0046 g

Step 2: Calculate the volume of O2 and H2 released
- 40% of the current is utilized for hydrogen evolution
- For hydrogen evolution, 2 moles of electrons are required for 1 mole of H2
- For 15 C of charge passed, 1 mole of H2 is evolved
- Volume of H2 at STP = 22.4 L/mol
- Volume of H2 released = 22.4 L/mol × 7.82 × 10^-5 mol = 1.756 × 10^-3 L
- For oxygen evolution, 4 moles of electrons are required for 1 mole of O2
- For 15 C of charge passed, 2 moles of O2 are evolved
- Volume of O2 at STP = 22.4 L/mol
- Volume of O2 released = 22.4 L/mol × 2 × 7.82 × 10^-5 mol = 3.12 × 10^-3 L
Therefore, the volume of O2 and H2 released at STP are 3.13 liters and 1.76 liters, respectively.
So, the correct answer is (c) 3.13 liters, 1.76 liters.
Explore Courses for JEE exam
A current of 3amp was passed through nickel sulphate solution for five hours, using a square strip of platinum of 4 cm side as cathode. The current efficiency is 60% for the deposition of nickel. Then, thevolume of O2 and H2 (if the rest of 40% of current is utilised for hydrogen evolution) released at STP are (a) 3.13 lit, 2.51 lit(b) 1.88 lit, 2.51 lit (c) 3.13 lit, 1.88 lit (d) 3.13 lit, 6.26 lit?
Question Description
A current of 3amp was passed through nickel sulphate solution for five hours, using a square strip of platinum of 4 cm side as cathode. The current efficiency is 60% for the deposition of nickel. Then, thevolume of O2 and H2 (if the rest of 40% of current is utilised for hydrogen evolution) released at STP are (a) 3.13 lit, 2.51 lit(b) 1.88 lit, 2.51 lit (c) 3.13 lit, 1.88 lit (d) 3.13 lit, 6.26 lit? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A current of 3amp was passed through nickel sulphate solution for five hours, using a square strip of platinum of 4 cm side as cathode. The current efficiency is 60% for the deposition of nickel. Then, thevolume of O2 and H2 (if the rest of 40% of current is utilised for hydrogen evolution) released at STP are (a) 3.13 lit, 2.51 lit(b) 1.88 lit, 2.51 lit (c) 3.13 lit, 1.88 lit (d) 3.13 lit, 6.26 lit? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A current of 3amp was passed through nickel sulphate solution for five hours, using a square strip of platinum of 4 cm side as cathode. The current efficiency is 60% for the deposition of nickel. Then, thevolume of O2 and H2 (if the rest of 40% of current is utilised for hydrogen evolution) released at STP are (a) 3.13 lit, 2.51 lit(b) 1.88 lit, 2.51 lit (c) 3.13 lit, 1.88 lit (d) 3.13 lit, 6.26 lit?.
Solutions for A current of 3amp was passed through nickel sulphate solution for five hours, using a square strip of platinum of 4 cm side as cathode. The current efficiency is 60% for the deposition of nickel. Then, thevolume of O2 and H2 (if the rest of 40% of current is utilised for hydrogen evolution) released at STP are (a) 3.13 lit, 2.51 lit(b) 1.88 lit, 2.51 lit (c) 3.13 lit, 1.88 lit (d) 3.13 lit, 6.26 lit? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of A current of 3amp was passed through nickel sulphate solution for five hours, using a square strip of platinum of 4 cm side as cathode. The current efficiency is 60% for the deposition of nickel. Then, thevolume of O2 and H2 (if the rest of 40% of current is utilised for hydrogen evolution) released at STP are (a) 3.13 lit, 2.51 lit(b) 1.88 lit, 2.51 lit (c) 3.13 lit, 1.88 lit (d) 3.13 lit, 6.26 lit? defined & explained in the simplest way possible. Besides giving the explanation of A current of 3amp was passed through nickel sulphate solution for five hours, using a square strip of platinum of 4 cm side as cathode. The current efficiency is 60% for the deposition of nickel. Then, thevolume of O2 and H2 (if the rest of 40% of current is utilised for hydrogen evolution) released at STP are (a) 3.13 lit, 2.51 lit(b) 1.88 lit, 2.51 lit (c) 3.13 lit, 1.88 lit (d) 3.13 lit, 6.26 lit?, a detailed solution for A current of 3amp was passed through nickel sulphate solution for five hours, using a square strip of platinum of 4 cm side as cathode. The current efficiency is 60% for the deposition of nickel. Then, thevolume of O2 and H2 (if the rest of 40% of current is utilised for hydrogen evolution) released at STP are (a) 3.13 lit, 2.51 lit(b) 1.88 lit, 2.51 lit (c) 3.13 lit, 1.88 lit (d) 3.13 lit, 6.26 lit? has been provided alongside types of A current of 3amp was passed through nickel sulphate solution for five hours, using a square strip of platinum of 4 cm side as cathode. The current efficiency is 60% for the deposition of nickel. Then, thevolume of O2 and H2 (if the rest of 40% of current is utilised for hydrogen evolution) released at STP are (a) 3.13 lit, 2.51 lit(b) 1.88 lit, 2.51 lit (c) 3.13 lit, 1.88 lit (d) 3.13 lit, 6.26 lit? theory, EduRev gives you an ample number of questions to practice A current of 3amp was passed through nickel sulphate solution for five hours, using a square strip of platinum of 4 cm side as cathode. The current efficiency is 60% for the deposition of nickel. Then, thevolume of O2 and H2 (if the rest of 40% of current is utilised for hydrogen evolution) released at STP are (a) 3.13 lit, 2.51 lit(b) 1.88 lit, 2.51 lit (c) 3.13 lit, 1.88 lit (d) 3.13 lit, 6.26 lit? tests, examples and also practice JEE tests.
Explore Courses for JEE exam

Top Courses for JEE

Explore Courses
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev