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The charge deposited on 4μF capacitor in the circuit is\
- a)6 x 10-6 C
- b)12 x 10-6 C
- c)24 x 10-6 C
- d)36 x 10-6 C
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
The charge deposited on 4μF capacitor in the circuit is\a)6 x 10-6C...
The charge on a 4μF capacitor can be calculated using the formula:
- Q = C × V where:
- Q is the charge in coulombs,
- C is the capacitance in farads, and
- V is the voltage across the capacitor in volts.
Given that the capacitance is 4μF (or 4 × 10-6 F), you need to know the voltage applied to find the charge.
If the voltage across the capacitor is V volts, then:
- The charge Q will be 4 × 10-6 F × V.
To determine the exact charge, you should substitute the value of V into the equation.
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