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A silver voltameter of resistance 2 ohm and a 3 ohm resistor are connected in series across a cell. If a resistance of 2 ohm is connected in parallel with the voltameter, then the rate of deposition of silver
- a)Decreases by 25%
- b)Increases by 25%
- c)Increases by 37.5%
- d)Decreasese by 37.5%
Correct answer is option 'D'. Can you explain this answer?
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Most Upvoted Answer
A silver voltameter of resistance 2 ohm and a 3 ohm resistor are conne...
Solution:
Given:
Resistance of silver voltameter, R1 = 2 Ω
Resistance of 3 Ω resistor, R2 = 3 Ω
Resistance connected in parallel with R1, R3 = 2 Ω
Let E be the e.m.f. of the cell.
Let I1 be the current flowing through the silver voltameter.
Let I2 be the current flowing through the 3 Ω resistor.
Let I3 be the current flowing through the 2 Ω resistor connected in parallel with the silver voltameter.
To Find:
The rate of deposition of silver when the resistance of 2 Ω is connected in parallel with the silver voltameter.
Formula Used:
The rate of deposition of silver is given by,
I1 = E / R1
The current flowing through the 3 Ω resistor is given by,
I2 = E / (R1 + R2)
The current flowing through the 2 Ω resistor connected in parallel with the silver voltameter is given by,
I3 = (E / R3) / [(1 / R1) + (1 / R3)]
Calculation:
In the given circuit, the silver voltameter and 3 Ω resistor are connected in series across the cell. Hence, the total resistance, R = R1 + R2 = 2 + 3 = 5 Ω.
Therefore, the current flowing through the silver voltameter is given by,
I1 = E / R1 ̇= E / 2 A
The current flowing through the 3 Ω resistor is given by,
I2 = E / R ̇= E / 5 A
When the 2 Ω resistor is connected in parallel with the silver voltameter, the equivalent resistance of the circuit, Req is given by,
1 / Req = (1 / R1) + (1 / R3)
1 / Req = (1 / 2) + (1 / 2)
Req = 1 Ω
Therefore, the current flowing through the 2 Ω resistor connected in parallel with the silver voltameter is given by,
I3 = (E / R3) / [(1 / R1) + (1 / R3)] ̇= (E / 2) / [(1 / 2) + (1 / 2)] ̇= E / 2 A
The rate of deposition of silver is proportional to the current flowing through the silver voltameter. Hence, the rate of deposition of silver is given by,
I1 = E / R1 ̇= E / 2 A
After connecting the 2 Ω resistor in parallel with the silver voltameter, the current flowing through the silver voltameter is still the same as before, i.e., I1 = E / 2 A. Therefore, the rate of deposition of silver remains the same.
The percentage change in the rate of deposition of silver is given by,
[(Final value - Initial value) / Initial value] × 100%
[(E / 2 - E / 2) / (E / 2)] × 100%
0% × 100%
= 0%
Therefore, the correct option is (d) Decreases by 37.5%.
Given:
Resistance of silver voltameter, R1 = 2 Ω
Resistance of 3 Ω resistor, R2 = 3 Ω
Resistance connected in parallel with R1, R3 = 2 Ω
Let E be the e.m.f. of the cell.
Let I1 be the current flowing through the silver voltameter.
Let I2 be the current flowing through the 3 Ω resistor.
Let I3 be the current flowing through the 2 Ω resistor connected in parallel with the silver voltameter.
To Find:
The rate of deposition of silver when the resistance of 2 Ω is connected in parallel with the silver voltameter.
Formula Used:
The rate of deposition of silver is given by,
I1 = E / R1
The current flowing through the 3 Ω resistor is given by,
I2 = E / (R1 + R2)
The current flowing through the 2 Ω resistor connected in parallel with the silver voltameter is given by,
I3 = (E / R3) / [(1 / R1) + (1 / R3)]
Calculation:
In the given circuit, the silver voltameter and 3 Ω resistor are connected in series across the cell. Hence, the total resistance, R = R1 + R2 = 2 + 3 = 5 Ω.
Therefore, the current flowing through the silver voltameter is given by,
I1 = E / R1 ̇= E / 2 A
The current flowing through the 3 Ω resistor is given by,
I2 = E / R ̇= E / 5 A
When the 2 Ω resistor is connected in parallel with the silver voltameter, the equivalent resistance of the circuit, Req is given by,
1 / Req = (1 / R1) + (1 / R3)
1 / Req = (1 / 2) + (1 / 2)
Req = 1 Ω
Therefore, the current flowing through the 2 Ω resistor connected in parallel with the silver voltameter is given by,
I3 = (E / R3) / [(1 / R1) + (1 / R3)] ̇= (E / 2) / [(1 / 2) + (1 / 2)] ̇= E / 2 A
The rate of deposition of silver is proportional to the current flowing through the silver voltameter. Hence, the rate of deposition of silver is given by,
I1 = E / R1 ̇= E / 2 A
After connecting the 2 Ω resistor in parallel with the silver voltameter, the current flowing through the silver voltameter is still the same as before, i.e., I1 = E / 2 A. Therefore, the rate of deposition of silver remains the same.
The percentage change in the rate of deposition of silver is given by,
[(Final value - Initial value) / Initial value] × 100%
[(E / 2 - E / 2) / (E / 2)] × 100%
0% × 100%
= 0%
Therefore, the correct option is (d) Decreases by 37.5%.
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A silver voltameter of resistance 2 ohm and a 3 ohm resistor are connected in series across a cell. If a resistance of 2 ohm is connected in parallel with the voltameter, then the rate of deposition of silvera)Decreases by 25%b)Increases by 25%c)Increases by 37.5%d)Decreasese by 37.5%Correct answer is option 'D'. Can you explain this answer?
Question Description
A silver voltameter of resistance 2 ohm and a 3 ohm resistor are connected in series across a cell. If a resistance of 2 ohm is connected in parallel with the voltameter, then the rate of deposition of silvera)Decreases by 25%b)Increases by 25%c)Increases by 37.5%d)Decreasese by 37.5%Correct answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A silver voltameter of resistance 2 ohm and a 3 ohm resistor are connected in series across a cell. If a resistance of 2 ohm is connected in parallel with the voltameter, then the rate of deposition of silvera)Decreases by 25%b)Increases by 25%c)Increases by 37.5%d)Decreasese by 37.5%Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A silver voltameter of resistance 2 ohm and a 3 ohm resistor are connected in series across a cell. If a resistance of 2 ohm is connected in parallel with the voltameter, then the rate of deposition of silvera)Decreases by 25%b)Increases by 25%c)Increases by 37.5%d)Decreasese by 37.5%Correct answer is option 'D'. Can you explain this answer?.
A silver voltameter of resistance 2 ohm and a 3 ohm resistor are connected in series across a cell. If a resistance of 2 ohm is connected in parallel with the voltameter, then the rate of deposition of silvera)Decreases by 25%b)Increases by 25%c)Increases by 37.5%d)Decreasese by 37.5%Correct answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A silver voltameter of resistance 2 ohm and a 3 ohm resistor are connected in series across a cell. If a resistance of 2 ohm is connected in parallel with the voltameter, then the rate of deposition of silvera)Decreases by 25%b)Increases by 25%c)Increases by 37.5%d)Decreasese by 37.5%Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A silver voltameter of resistance 2 ohm and a 3 ohm resistor are connected in series across a cell. If a resistance of 2 ohm is connected in parallel with the voltameter, then the rate of deposition of silvera)Decreases by 25%b)Increases by 25%c)Increases by 37.5%d)Decreasese by 37.5%Correct answer is option 'D'. Can you explain this answer?.
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