The least number of cells each of emf 2v and internal resistance 0.5 o...
Calculating the EMF and Internal Resistance of a Cell
To find the minimum number of cells required to produce a current of 2 amperes in an external resistance of 4 ohms, we need to first calculate the EMF and internal resistance of a single cell.
Using Ohm's Law to Calculate Current
We can use Ohm's Law to calculate the current produced by a single cell:
I = E / (R + r)
Where I is the current, E is the EMF, R is the external resistance, and r is the internal resistance.
Solving for EMF and Internal Resistance
We know that we want the current to be 2 amperes and the external resistance to be 4 ohms. We also know that the internal resistance of each cell is 0.5 ohms.
So, we can set up the equation:
2 = E / (4 + 0.5)
Solving for E, we get:
E = 9 volts
Now that we know the EMF of each cell is 9 volts, we can calculate the number of cells needed to produce a current of 2 amperes.
Calculating the Number of Cells Needed
Each cell has an EMF of 9 volts and an internal resistance of 0.5 ohms. To produce a current of 2 amperes in an external resistance of 4 ohms, we need a total voltage of:
V = IR = 2 * 4 = 8 volts
To get a total voltage of 8 volts with cells that have an EMF of 9 volts each, we need:
N = V / E = 8 / 9 = 0.88
Since we can't have a fraction of a cell, we round up to get:
N = 1
Therefore, we need at least one cell with an EMF of 9 volts and an internal resistance of 0.5 ohms to produce a current of 2 amperes in an external resistance of 4 ohms.
The least number of cells each of emf 2v and internal resistance 0.5 o...
Given ~£=2V r=0.5ohm R=4ohm I=2A
required~ n=?
solution ~if the connection is series
I=n£/R+nr=2A
n(2v)=2(4+0.5n)
2n-1n=8
n=8
if the connection is parallel
I=n£/nR+r=2A
n(2v)=2(n4.5+0.5)
2n-8n=1
n=-1/6 there is no -ve number of cell
so the connection is in series. n=8