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A particle is moving in a circle with uniform speed υ. In moving from a point to another diametrically opposite point
- a)The momentum changes by mυ
- b)The momentum changes by 2mυ
- c)The kinetic energy changes by (1/2)mυ2
- d)The kinetic energy changes by mυ2
Correct answer is option 'B'. Can you explain this answer?
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A particle is moving in a circle with uniform speed υ. In movi...
Momentum changes by 2mv but kinetic energy remains same.
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A particle is moving in a circle with uniform speed υ. In movi...
If a particle is moving in a circle with uniform speed, it means that the magnitude of its velocity is constant throughout the motion. However, the direction of its velocity is continuously changing as it moves around the circle.
This type of motion is called uniform circular motion. In uniform circular motion, the particle's acceleration is directed towards the center of the circle and is always perpendicular to the velocity vector. The magnitude of the acceleration is given by the equation:
a = (v^2) / r
where a is the magnitude of the acceleration, v is the magnitude of the velocity, and r is the radius of the circle.
Since the speed is constant, the magnitude of the velocity is also constant, so the acceleration is solely determined by the radius of the circle. The smaller the radius, the larger the acceleration required to keep the particle moving in a circle.
It is important to note that even though the speed is constant, the particle is still accelerating because acceleration is defined as any change in velocity, including changes in direction.
This type of motion is called uniform circular motion. In uniform circular motion, the particle's acceleration is directed towards the center of the circle and is always perpendicular to the velocity vector. The magnitude of the acceleration is given by the equation:
a = (v^2) / r
where a is the magnitude of the acceleration, v is the magnitude of the velocity, and r is the radius of the circle.
Since the speed is constant, the magnitude of the velocity is also constant, so the acceleration is solely determined by the radius of the circle. The smaller the radius, the larger the acceleration required to keep the particle moving in a circle.
It is important to note that even though the speed is constant, the particle is still accelerating because acceleration is defined as any change in velocity, including changes in direction.
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Community Answer
A particle is moving in a circle with uniform speed υ. In movi...
Initial velocity v1 = v
Final velocity v2 = -v
Initial momentum p1 = mv
Final momentum p2 = m(-v) = -mv
Change in momentum
Δp = p1 - p2
⇒ mv - (-mv)
⇒ 2mv
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A particle is moving in a circle with uniform speed υ. In moving from a point to another diametrically opposite pointa)The momentum changes by mυb)The momentum changes by 2mυc)The kinetic energy changes by (1/2)mυ2d)The kinetic energy changes by mυ2Correct answer is option 'B'. Can you explain this answer?
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A particle is moving in a circle with uniform speed υ. In moving from a point to another diametrically opposite pointa)The momentum changes by mυb)The momentum changes by 2mυc)The kinetic energy changes by (1/2)mυ2d)The kinetic energy changes by mυ2Correct answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A particle is moving in a circle with uniform speed υ. In moving from a point to another diametrically opposite pointa)The momentum changes by mυb)The momentum changes by 2mυc)The kinetic energy changes by (1/2)mυ2d)The kinetic energy changes by mυ2Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A particle is moving in a circle with uniform speed υ. In moving from a point to another diametrically opposite pointa)The momentum changes by mυb)The momentum changes by 2mυc)The kinetic energy changes by (1/2)mυ2d)The kinetic energy changes by mυ2Correct answer is option 'B'. Can you explain this answer?.
A particle is moving in a circle with uniform speed υ. In moving from a point to another diametrically opposite pointa)The momentum changes by mυb)The momentum changes by 2mυc)The kinetic energy changes by (1/2)mυ2d)The kinetic energy changes by mυ2Correct answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A particle is moving in a circle with uniform speed υ. In moving from a point to another diametrically opposite pointa)The momentum changes by mυb)The momentum changes by 2mυc)The kinetic energy changes by (1/2)mυ2d)The kinetic energy changes by mυ2Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A particle is moving in a circle with uniform speed υ. In moving from a point to another diametrically opposite pointa)The momentum changes by mυb)The momentum changes by 2mυc)The kinetic energy changes by (1/2)mυ2d)The kinetic energy changes by mυ2Correct answer is option 'B'. Can you explain this answer?.
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