Problem: Dheeraj has twice as many sisters as he has brothers. If Deepa, Dheeraj's sister has the same number of brothers as she has sisters, then how many brothers does Deepa have?

Solution:

Let's assume that Dheeraj has 'x' number of brothers.

According to the problem, Dheeraj has twice as many sisters as brothers. Therefore, the number of sisters that Dheeraj has is 2x.

Now, let's calculate the total number of siblings that Dheeraj has.

Total siblings = Number of brothers + Number of sisters
Total siblings = x + 2x
Total siblings = 3x

So, Dheeraj has a total of 3x siblings.

Now, let's move to the second part of the problem. It is given that Deepa has the same number of brothers as she has sisters. Let's assume that Deepa has 'y' number of sisters.

According to the problem, Deepa has the same number of brothers as sisters. Therefore, the number of brothers that Deepa has is also 'y'.

Now, let's calculate the total number of siblings that Deepa has.

Total siblings = Number of brothers + Number of sisters
Total siblings = y + y
Total siblings = 2y

So, Deepa has a total of 2y siblings.

We know that Dheeraj and Deepa are siblings. Therefore, their total number of siblings should be the same.

3x = 2y

We need to find the value of 'y', which represents the number of sisters that Deepa has.

Let's assume that Dheeraj has 2 brothers.

x = 2

Now, let's substitute the value of 'x' in the equation we derived earlier.

3x = 2y
3(2) = 2y
6 = 2y
y = 3

So, Deepa has 3 sisters and 3 brothers, including Dheeraj.

Therefore, Deepa has 3 brothers.