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Lata has the same number of sisters as she has brothers, but her brother Shyam has twice as many sisters as he has brothers. How many children are there in the family?
- a)7
- b)6
- c)5
- d)4
- e)None of these
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
Lata has the same number of sisters as she has brothers, but her brot...
Lata's case: number of brothers = numbers of sisters, i.e B = S
Shyam's Case : No of brothers * 2 = number of sisters, so 2b=s
No of sisters for shyam is doubled, going by options:
Answer should be an odd number, as leaving them, they are getting even numbers. i.e. B=S, addition of any with itself will give an even number. Same with the second case. So option 2 & 4 can be eliminated.
Consider option 3: i.e. 5. It won't satisfy both cases.
5 - lata = 4 people, 2 brothers, 2 sis → Satisfied 5 - Shyam = 4 people, no right possible combination →
Not satisfied
Consider option 1: 7
It satisfies both with a combination of 4 females & 3 males.
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Community Answer
Lata has the same number of sisters as she has brothers, but her brot...
Given:
- Lata has the same number of sisters as she has brothers.
- Shyam has twice as many sisters as he has brothers.
Let's assume:
- Lata has 'x' sisters and 'x' brothers.
- Shyam has 'y' sisters and 'z' brothers.
We know that:
- Lata has 'x' sisters and 'x' brothers. So, the total number of children in Lata's family is '2x'.
- Shyam has twice as many sisters as he has brothers. So, the total number of sisters in Shyam's family is '2z' and the total number of brothers is 'z'. Hence, the total number of children in Shyam's family is '2z + z = 3z'.
As the two families are the same, the total number of children in both families should be equal.
Therefore, we can write:
2x = 3z
As both 'x' and 'z' are positive integers, we can say that:
- If x is odd, then z will be even.
- If x is even, then z will be a multiple of 3.
Now, let's try to find the values of 'x' and 'z' that satisfy the above equation.
- Let's assume x = 1, then z = 2/3 (which is not possible as 'z' should be a positive integer).
- Let's assume x = 2, then z = 4/3 (which is not possible as 'z' should be a positive integer).
- Let's assume x = 3, then z = 2 (which satisfies the equation).
Therefore, the total number of children in the family is:
2x = 2*3 = 6
Hence, the correct option is (A) 7.
- Lata has the same number of sisters as she has brothers.
- Shyam has twice as many sisters as he has brothers.
Let's assume:
- Lata has 'x' sisters and 'x' brothers.
- Shyam has 'y' sisters and 'z' brothers.
We know that:
- Lata has 'x' sisters and 'x' brothers. So, the total number of children in Lata's family is '2x'.
- Shyam has twice as many sisters as he has brothers. So, the total number of sisters in Shyam's family is '2z' and the total number of brothers is 'z'. Hence, the total number of children in Shyam's family is '2z + z = 3z'.
As the two families are the same, the total number of children in both families should be equal.
Therefore, we can write:
2x = 3z
As both 'x' and 'z' are positive integers, we can say that:
- If x is odd, then z will be even.
- If x is even, then z will be a multiple of 3.
Now, let's try to find the values of 'x' and 'z' that satisfy the above equation.
- Let's assume x = 1, then z = 2/3 (which is not possible as 'z' should be a positive integer).
- Let's assume x = 2, then z = 4/3 (which is not possible as 'z' should be a positive integer).
- Let's assume x = 3, then z = 2 (which satisfies the equation).
Therefore, the total number of children in the family is:
2x = 2*3 = 6
Hence, the correct option is (A) 7.
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Lata has the same number of sisters as she has brothers, but her brother Shyam has twice as many sisters as he has brothers. How many children are there in the family?a) 7b) 6c) 5d) 4e) None of theseCorrect answer is option 'A'. Can you explain this answer?
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