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The age of a person is twice the sum of the ahes of his two sons and five years ago his age was thrice the sum of their ages. Find his present age?
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The age of a person is twice the sum of the ahes of his two sons and f...
Problem:
The age of a person is twice the sum of the ahes of his two sons and five years ago his age was thrice the sum of their ages. Find his present age?
Solution:
Let the present age of the person be "P" and the present ages of his two sons be "S1" and "S2".
Step 1: Formulating Equations
According to the problem statement, we have two equations:
1. P = 2(S1 + S2)
2. (P - 5) = 3(S1 - 5 + S2 - 5)
Simplifying the equations, we get:
1. P = 2S1 + 2S2
2. P - 5 = 3S1 - 15 + 3S2 - 15
P = 3S1 + 3S2 - 5 + 15 + 15
P = 3S1 + 3S2 + 25
Step 2: Solving Equations
We can solve the above two equations to get the values of P, S1, and S2.
From equation (1), we have:
P = 2S1 + 2S2
Substituting the value of P in equation (2), we get:
3S1 + 3S2 + 25 = 2S1 + 2S2
Simplifying the equation, we get:
S1 + S2 = 8
Substituting the value of S1 + S2 in equation (1), we get:
P = 2(S1 + S2) = 2(8) = 16
Therefore, the present age of the person is 16 years.
Step 3: Verification
We can verify our solution by checking if the conditions given in the problem statement are satisfied.
Five years ago, the person's age was 11 and the sum of his sons' ages was 3(S1 - 5 + S2 - 5) = 6.
Therefore, the conditions are satisfied and our solution is correct.
Conclusion:
The present age of the person is 16 years.
The age of a person is twice the sum of the ahes of his two sons and five years ago his age was thrice the sum of their ages. Find his present age?
Solution:
Let the present age of the person be "P" and the present ages of his two sons be "S1" and "S2".
Step 1: Formulating Equations
According to the problem statement, we have two equations:
1. P = 2(S1 + S2)
2. (P - 5) = 3(S1 - 5 + S2 - 5)
Simplifying the equations, we get:
1. P = 2S1 + 2S2
2. P - 5 = 3S1 - 15 + 3S2 - 15
P = 3S1 + 3S2 - 5 + 15 + 15
P = 3S1 + 3S2 + 25
Step 2: Solving Equations
We can solve the above two equations to get the values of P, S1, and S2.
From equation (1), we have:
P = 2S1 + 2S2
Substituting the value of P in equation (2), we get:
3S1 + 3S2 + 25 = 2S1 + 2S2
Simplifying the equation, we get:
S1 + S2 = 8
Substituting the value of S1 + S2 in equation (1), we get:
P = 2(S1 + S2) = 2(8) = 16
Therefore, the present age of the person is 16 years.
Step 3: Verification
We can verify our solution by checking if the conditions given in the problem statement are satisfied.
Five years ago, the person's age was 11 and the sum of his sons' ages was 3(S1 - 5 + S2 - 5) = 6.
Therefore, the conditions are satisfied and our solution is correct.
Conclusion:
The present age of the person is 16 years.
Community Answer
The age of a person is twice the sum of the ahes of his two sons and f...
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The age of a person is twice the sum of the ahes of his two sons and five years ago his age was thrice the sum of their ages. Find his present age?
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The age of a person is twice the sum of the ahes of his two sons and five years ago his age was thrice the sum of their ages. Find his present age? for CA Foundation 2024 is part of CA Foundation preparation. The Question and answers have been prepared according to the CA Foundation exam syllabus. Information about The age of a person is twice the sum of the ahes of his two sons and five years ago his age was thrice the sum of their ages. Find his present age? covers all topics & solutions for CA Foundation 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The age of a person is twice the sum of the ahes of his two sons and five years ago his age was thrice the sum of their ages. Find his present age?.
The age of a person is twice the sum of the ahes of his two sons and five years ago his age was thrice the sum of their ages. Find his present age? for CA Foundation 2024 is part of CA Foundation preparation. The Question and answers have been prepared according to the CA Foundation exam syllabus. Information about The age of a person is twice the sum of the ahes of his two sons and five years ago his age was thrice the sum of their ages. Find his present age? covers all topics & solutions for CA Foundation 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The age of a person is twice the sum of the ahes of his two sons and five years ago his age was thrice the sum of their ages. Find his present age?.
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