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The age of a person is twice the sum of the age of his 2 son and 5 years ago his age was thrice the sum of their ages. Find his present age?
Most Upvoted Answer
The age of a person is twice the sum of the age of his 2 son and 5 yea...
Problem: The age of a person is twice the sum of the age of his 2 sons and 5 years ago his age was thrice the sum of their ages. Find his present age?

Solution:

Let the present age of the person be 'P'.
Let the present age of his first son be 'S1'.
Let the present age of his second son be 'S2'.

Given, P = 2(S1 + S2) ...(1) (Age of a person is twice the sum of the age of his 2 sons)
and, P - 5 = 3(S1 - 5 + S2 - 5) ...(2) (5 years ago his age was thrice the sum of their ages)

Simplifying equation (2), we get:
P - 5 = 3(S1 + S2 - 10)
P - 5 = 3S1 + 3S2 - 30
P = 3S1 + 3S2 - 25 ...(3)

Substituting equation (3) in equation (1), we get:
3S1 + 3S2 - 25 = 2(S1 + S2)
3S1 + 3S2 - 25 = 2S1 + 2S2
Simplifying the above equation, we get:
S1 + S2 = 25 ...(4)

Substituting equation (4) in equation (1), we get:
P = 2(25)
P = 50

Therefore, the present age of the person is 50 years.

Answer: The present age of the person is 50 years.
Community Answer
The age of a person is twice the sum of the age of his 2 son and 5 yea...
Let x be the present age of man and
y be the sum of the present ages of the two sons

the age of a person is twice the sum of his two sons

x = 2y --i)


5 years ago age of the man ( x - 5 ) was thrice the sum of their ages

so
x-5 = 3 (y-5-5) ---ii)

here y is sum of ages so we have to do -5 two times

now substitute i) in ii)
we get
2y-5 = 3(y-10)

2y -5 = 3y-30

-5+30 = 3y - 2y

y = 25

x is 2 X 25 = 50 which is present age of the man
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The age of a person is twice the sum of the age of his 2 son and 5 years ago his age was thrice the sum of their ages. Find his present age?
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