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If a function is described by F = (3x + z, y2 − sin x2z, xz + yex5), then the divergence theorem value in the region 0<x<1, 0<y<3 and 0<z<2 will be
  • a)
    13
  • b)
    26
  • c)
    39
  • d)
    51
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
If a function is described by F = (3x + z, y2− sin x2z, xz + yex...
Answer: c
Explanation: Div (F) = 3 + 2y + x. By divergence theorem, the triple integral of Div F in the region is ∫∫∫ (3 + 2y + x) dx dy dz. On integrating from x = 0->1, y = 0->3 and z = 0->2, we get 39 units.
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If a function is described by F = (3x + z, y2− sin x2z, xz + yex...
The function is not properly described as it is missing information about the variables and their relationships. Please provide more context or a complete description of the function.
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