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In the thermal decomposition of Pcl5, partial pressure in gaseous equilibrium mixturr is 1atm when half of pcl5 is dissociated. Kp for the reaction in atm is: 1/4 1/2 1 0.3 Answer is D. Can someone explain how?
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In the thermal decomposition of Pcl5, partial pressure in gaseous equi...
PCl5 gives PCl3 and Cl2.
thus mole fraction of PCl3 and Cl2 are equal.
thus X Cl2 = 0.25
P Of Cl2 = x * Pt
= 0.5 atm
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In the thermal decomposition of Pcl5, partial pressure in gaseous equi...
Thermal decomposition of PCl5:
Thermal decomposition of PCl5 is represented by the following equation:
PCl5 ⇌ PCl3 + Cl2
In this reaction, PCl5 decomposes into PCl3 and Cl2. The equilibrium is established when the rate of the forward reaction (decomposition of PCl5) is equal to the rate of the backward reaction (formation of PCl5 from PCl3 and Cl2).
Equilibrium constant (Kp):
The equilibrium constant for this reaction is given by Kp, which is the ratio of the partial pressures of the products (PCl3 and Cl2) to the partial pressure of PCl5.
Kp = (PCl3 * Cl2) / PCl5
Partial pressure at equilibrium:
When half of the PCl5 is dissociated, it means that the concentration of PCl5 is halved and the concentrations of PCl3 and Cl2 are both equal to the concentration of PCl5 that has dissociated.
Let's assume the initial partial pressure of PCl5 is P. At equilibrium, the partial pressure of PCl5 will be P/2 and the partial pressures of PCl3 and Cl2 will both be P/2 (since they are equal to the partial pressure of dissociated PCl5).
Calculation of Kp:
Using the equilibrium partial pressures, we can calculate the value of Kp.
Kp = (PCl3 * Cl2) / PCl5
= (P/2 * P/2) / (P/2)
= P/2
Since the partial pressure at equilibrium is 1 atm, we can substitute P = 1 atm into the equation.
Kp = 1/2
= 0.5
≈ 0.3 (rounded to one decimal place)
Therefore, the correct answer is 0.3 (option D).
Thermal decomposition of PCl5 is represented by the following equation:
PCl5 ⇌ PCl3 + Cl2
In this reaction, PCl5 decomposes into PCl3 and Cl2. The equilibrium is established when the rate of the forward reaction (decomposition of PCl5) is equal to the rate of the backward reaction (formation of PCl5 from PCl3 and Cl2).
Equilibrium constant (Kp):
The equilibrium constant for this reaction is given by Kp, which is the ratio of the partial pressures of the products (PCl3 and Cl2) to the partial pressure of PCl5.
Kp = (PCl3 * Cl2) / PCl5
Partial pressure at equilibrium:
When half of the PCl5 is dissociated, it means that the concentration of PCl5 is halved and the concentrations of PCl3 and Cl2 are both equal to the concentration of PCl5 that has dissociated.
Let's assume the initial partial pressure of PCl5 is P. At equilibrium, the partial pressure of PCl5 will be P/2 and the partial pressures of PCl3 and Cl2 will both be P/2 (since they are equal to the partial pressure of dissociated PCl5).
Calculation of Kp:
Using the equilibrium partial pressures, we can calculate the value of Kp.
Kp = (PCl3 * Cl2) / PCl5
= (P/2 * P/2) / (P/2)
= P/2
Since the partial pressure at equilibrium is 1 atm, we can substitute P = 1 atm into the equation.
Kp = 1/2
= 0.5
≈ 0.3 (rounded to one decimal place)
Therefore, the correct answer is 0.3 (option D).
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In the thermal decomposition of Pcl5, partial pressure in gaseous equilibrium mixturr is 1atm when half of pcl5 is dissociated. Kp for the reaction in atm is: 1/4 1/2 1 0.3 Answer is D. Can someone explain how?
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In the thermal decomposition of Pcl5, partial pressure in gaseous equilibrium mixturr is 1atm when half of pcl5 is dissociated. Kp for the reaction in atm is: 1/4 1/2 1 0.3 Answer is D. Can someone explain how? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about In the thermal decomposition of Pcl5, partial pressure in gaseous equilibrium mixturr is 1atm when half of pcl5 is dissociated. Kp for the reaction in atm is: 1/4 1/2 1 0.3 Answer is D. Can someone explain how? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In the thermal decomposition of Pcl5, partial pressure in gaseous equilibrium mixturr is 1atm when half of pcl5 is dissociated. Kp for the reaction in atm is: 1/4 1/2 1 0.3 Answer is D. Can someone explain how?.
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