Explanation:
Let the zeroes of the quadratic polynomial px^2 + 2x + 3q be α and β.

Then, sum of the zeroes = α + β
Product of the zeroes = αβ

Given, sum of the zeroes + sum of the coefficients = product of the zeroes.

α + β + 2 + 3q = αβ

Rearranging the terms, we get:

αβ - α - β - 2 - 3q = 0

Now, we can rewrite the left-hand side of the equation as a product of two linear factors:

(α - 1)(β - 1) - 3(q + 1) = 0

Since the product of two linear factors is zero if and only if at least one of the factors is zero, we have two cases to consider:

Case 1: α - 1 = 0

This implies that α = 1, and substituting this into the equation α + β + 2 + 3q = αβ gives us:

1 + β + 2 + 3q = β

Simplifying, we get:

3q - 1 = 0

Therefore, q = 1/3.

Case 2: β - 1 = 0

This implies that β = 1, and substituting this into the equation α + β + 2 + 3q = αβ gives us:

α + 1 + 2 + 3q = α

Simplifying, we get:

3q + 3 = 0

Therefore, q = -1.

Conclusion:
Thus, we have found that the value of q can either be 1/3 or -1. However, we cannot determine the value of p from the given information, as there are infinitely many quadratic polynomials that satisfy the condition that their sum and zeroes are equal to their product of zeroes.

P(0)=2 +2(0) + 3q =2+ 0 3q =2+ 3q =3q = ‐2 q = ‐2/3 So, the value of "p" is ‐2/3