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A hammer weighing 1 kg moving with a speed of 10m/s strikes the head of a nail driving it 10cm into a wall Neglecting the mass of the nail calculate 1) ?The acceleration 2) time interval 3) impulse?
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A hammer weighing 1 kg moving with a speed of 10m/s strikes the head o...
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A hammer weighing 1 kg moving with a speed of 10m/s strikes the head o...
1) The acceleration:
To calculate the acceleration, we can use the equation:
Acceleration (a) = Change in velocity (Δv) / Time taken (Δt)
Given that the hammer is initially at rest and then moves with a speed of 10 m/s, the change in velocity is:
Δv = 10 m/s
However, we need to find the time interval first.
2) The time interval:
To find the time interval, we can use the equation:
Distance (d) = Initial velocity (u) × Time (t) + (1/2) × Acceleration (a) × Time (t)^2
In this case, the hammer strikes the nail and drives it 10 cm into the wall, which is equivalent to a distance of 0.1 m. The initial velocity is zero since the hammer is at rest initially. We can rearrange the equation to solve for time:
0.1 m = 0 × t + (1/2) × a × t^2
0.1 m = (1/2) × a × t^2
Now we have two equations with two unknowns: a and t. We can substitute the value of acceleration (Δv / Δt) into the second equation and solve for time.
3) The impulse:
Impulse is defined as the change in momentum. Momentum (p) is calculated by multiplying mass (m) by velocity (v):
Momentum (p) = mass (m) × velocity (v)
Since the nail's mass is neglected, the momentum before and after the strike will be the same. Therefore, the impulse is zero.
To summarize:
1) The acceleration can be calculated using the equation a = Δv / Δt.
2) The time interval can be found by solving the equation 0.1 m = (1/2) × a × t^2.
3) The impulse is zero, as there is no change in momentum.
To calculate the acceleration, we can use the equation:
Acceleration (a) = Change in velocity (Δv) / Time taken (Δt)
Given that the hammer is initially at rest and then moves with a speed of 10 m/s, the change in velocity is:
Δv = 10 m/s
However, we need to find the time interval first.
2) The time interval:
To find the time interval, we can use the equation:
Distance (d) = Initial velocity (u) × Time (t) + (1/2) × Acceleration (a) × Time (t)^2
In this case, the hammer strikes the nail and drives it 10 cm into the wall, which is equivalent to a distance of 0.1 m. The initial velocity is zero since the hammer is at rest initially. We can rearrange the equation to solve for time:
0.1 m = 0 × t + (1/2) × a × t^2
0.1 m = (1/2) × a × t^2
Now we have two equations with two unknowns: a and t. We can substitute the value of acceleration (Δv / Δt) into the second equation and solve for time.
3) The impulse:
Impulse is defined as the change in momentum. Momentum (p) is calculated by multiplying mass (m) by velocity (v):
Momentum (p) = mass (m) × velocity (v)
Since the nail's mass is neglected, the momentum before and after the strike will be the same. Therefore, the impulse is zero.
To summarize:
1) The acceleration can be calculated using the equation a = Δv / Δt.
2) The time interval can be found by solving the equation 0.1 m = (1/2) × a × t^2.
3) The impulse is zero, as there is no change in momentum.
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A hammer weighing 1 kg moving with a speed of 10m/s strikes the head of a nail driving it 10cm into a wall Neglecting the mass of the nail calculate 1) ?The acceleration 2) time interval 3) impulse?
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A hammer weighing 1 kg moving with a speed of 10m/s strikes the head of a nail driving it 10cm into a wall Neglecting the mass of the nail calculate 1) ?The acceleration 2) time interval 3) impulse? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A hammer weighing 1 kg moving with a speed of 10m/s strikes the head of a nail driving it 10cm into a wall Neglecting the mass of the nail calculate 1) ?The acceleration 2) time interval 3) impulse? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A hammer weighing 1 kg moving with a speed of 10m/s strikes the head of a nail driving it 10cm into a wall Neglecting the mass of the nail calculate 1) ?The acceleration 2) time interval 3) impulse?.
A hammer weighing 1 kg moving with a speed of 10m/s strikes the head of a nail driving it 10cm into a wall Neglecting the mass of the nail calculate 1) ?The acceleration 2) time interval 3) impulse? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A hammer weighing 1 kg moving with a speed of 10m/s strikes the head of a nail driving it 10cm into a wall Neglecting the mass of the nail calculate 1) ?The acceleration 2) time interval 3) impulse? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A hammer weighing 1 kg moving with a speed of 10m/s strikes the head of a nail driving it 10cm into a wall Neglecting the mass of the nail calculate 1) ?The acceleration 2) time interval 3) impulse?.
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