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Two masses M1 and M2 are connected by a light string passing over a smooth pulley. When set free M1 moves download by 2 metre in 2 second. the ratio of M1 : M2 is - A)9 : 7 B)11 : 9 C)13 : 11 D)15 : 13?
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Two masses M1 and M2 are connected by a light string passing over a sm...
Given Data:
- Distance moved by M1 = 2 meters
- Time taken for M1 to move = 2 seconds

Calculation:
- Let the acceleration of M1 be 'a' m/s²
- Using the equation of motion: s = ut + 0.5at²
- 2 = 0 + 0.5 * a * (2)²
- 2 = a * 2
- a = 1 m/s²

Calculating the masses:
- Let M1 = m1 kg and M2 = m2 kg
- For M1, F = Ma = m1 * 1 = m1
- For M2, F = Ma = m2 * 9.8 (acceleration due to gravity 'g') = 9.8m2
- As they are connected by a light string over a pulley, the tension in the string is the same for both masses
- Tension = m1 * a = m1 * 1 = m1 = 9.8m2

Ratio of M1 : M2:
- m1 = 9.8m2
- m1/m2 = 9.8
- m1 : m2 = 9.8 : 1
- Simplifying, we get m1 : m2 = 98 : 10
- Further simplifying, we get m1 : m2 = 49 : 5
The ratio of M1 : M2 is 49 : 5.
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Two masses M1 and M2 are connected by a light string passing over a sm...
11
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Two masses M1 and M2 are connected by a light string passing over a smooth pulley. When set free M1 moves download by 2 metre in 2 second. the ratio of M1 : M2 is - A)9 : 7 B)11 : 9 C)13 : 11 D)15 : 13?
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