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Cerium (Z = 58) is an important member of lanthanides. Which of the following statements about cerium is incorrect:
- a)Cerium IV acts as an oxidizing agent.
- b)The + 4 oxidation state of cerium is not known in solution.
- c)The + 3 oxidation state is more stable than the + 4 state.
- d)The common oxidation states of cerium are + 3 and + 4
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
Cerium (Z = 58) is an important member of lanthanides. Which of the fo...
- The incorrect statement about the Cerium is only the B option.
B: The +4 oxidation state of cerium is not known in solutions.
As +4 oxidation state, is common for the Cerium. - The correct statements about the Cerium are as follows:
A: Cerium (IV) acts as an oxidizing agent
C: The common oxidation state of Cerium are +3 and +4.
D: The +3 oxidation state of the Cerium is more stable than the +4 oxidation state.
Most Upvoted Answer
Cerium (Z = 58) is an important member of lanthanides. Which of the fo...
Incorrect statement: The 4 oxidation state of cerium is not known in solution.
Explanation:
Cerium is a member of the lanthanide series and has an atomic number of 58. It has a variety of oxidation states, including +3 and +4. Let's analyze each statement to determine which one is incorrect.
a) Cerium IV acts as an oxidizing agent:
This statement is correct. Cerium can exist in the +4 oxidation state, in which it acts as a strong oxidizing agent. Cerium(IV) compounds, such as cerium(IV) sulfate (Ce(SO4)2), can oxidize other species by donating electrons.
b) The 4 oxidation state of cerium is not known in solution:
This statement is incorrect. Cerium can exist in the +4 oxidation state in solution. Cerium(IV) compounds are often used in redox reactions and as catalysts in organic synthesis. For example, ceric ammonium nitrate [Ce(NH4)2(NO3)6] is a common reagent used for oxidation reactions in organic chemistry.
c) The 3 oxidation state is more stable than the 4 state:
This statement is correct. In general, the +3 oxidation state of cerium is more stable than the +4 oxidation state. This is due to the extra stability provided by the half-filled 4f subshell in the +3 oxidation state. The +3 oxidation state is the most common oxidation state of cerium in its compounds.
d) The common oxidation states of cerium are 3 and 4:
This statement is correct. The most common oxidation states of cerium are +3 and +4. Cerium can also exhibit other oxidation states, such as +2 and +6, but these are less common.
In conclusion, the incorrect statement is b) The 4 oxidation state of cerium is not known in solution. Cerium can exist in the +4 oxidation state in solution and is commonly used in redox reactions and as an oxidizing agent.
Explanation:
Cerium is a member of the lanthanide series and has an atomic number of 58. It has a variety of oxidation states, including +3 and +4. Let's analyze each statement to determine which one is incorrect.
a) Cerium IV acts as an oxidizing agent:
This statement is correct. Cerium can exist in the +4 oxidation state, in which it acts as a strong oxidizing agent. Cerium(IV) compounds, such as cerium(IV) sulfate (Ce(SO4)2), can oxidize other species by donating electrons.
b) The 4 oxidation state of cerium is not known in solution:
This statement is incorrect. Cerium can exist in the +4 oxidation state in solution. Cerium(IV) compounds are often used in redox reactions and as catalysts in organic synthesis. For example, ceric ammonium nitrate [Ce(NH4)2(NO3)6] is a common reagent used for oxidation reactions in organic chemistry.
c) The 3 oxidation state is more stable than the 4 state:
This statement is correct. In general, the +3 oxidation state of cerium is more stable than the +4 oxidation state. This is due to the extra stability provided by the half-filled 4f subshell in the +3 oxidation state. The +3 oxidation state is the most common oxidation state of cerium in its compounds.
d) The common oxidation states of cerium are 3 and 4:
This statement is correct. The most common oxidation states of cerium are +3 and +4. Cerium can also exhibit other oxidation states, such as +2 and +6, but these are less common.
In conclusion, the incorrect statement is b) The 4 oxidation state of cerium is not known in solution. Cerium can exist in the +4 oxidation state in solution and is commonly used in redox reactions and as an oxidizing agent.
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Cerium (Z = 58) is an important member of lanthanides. Which of the fo...
Ans.
Option (b)
The +4 oxidation state of cerium is not known in solutions
+3 and +4 states are shown by Ce in aqueous solution.
+3 and +4 states are shown by Ce in aqueous solution.
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Cerium (Z = 58) is an important member of lanthanides. Which of the following statements about cerium is incorrect:a)Cerium IV acts as an oxidizing agent.b)The + 4 oxidation state of cerium is not known in solution.c)The + 3 oxidation state is more stable than the + 4 state.d)The common oxidation states of cerium are + 3 and + 4Correct answer is option 'B'. Can you explain this answer?
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Cerium (Z = 58) is an important member of lanthanides. Which of the following statements about cerium is incorrect:a)Cerium IV acts as an oxidizing agent.b)The + 4 oxidation state of cerium is not known in solution.c)The + 3 oxidation state is more stable than the + 4 state.d)The common oxidation states of cerium are + 3 and + 4Correct answer is option 'B'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about Cerium (Z = 58) is an important member of lanthanides. Which of the following statements about cerium is incorrect:a)Cerium IV acts as an oxidizing agent.b)The + 4 oxidation state of cerium is not known in solution.c)The + 3 oxidation state is more stable than the + 4 state.d)The common oxidation states of cerium are + 3 and + 4Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Cerium (Z = 58) is an important member of lanthanides. Which of the following statements about cerium is incorrect:a)Cerium IV acts as an oxidizing agent.b)The + 4 oxidation state of cerium is not known in solution.c)The + 3 oxidation state is more stable than the + 4 state.d)The common oxidation states of cerium are + 3 and + 4Correct answer is option 'B'. Can you explain this answer?.
Cerium (Z = 58) is an important member of lanthanides. Which of the following statements about cerium is incorrect:a)Cerium IV acts as an oxidizing agent.b)The + 4 oxidation state of cerium is not known in solution.c)The + 3 oxidation state is more stable than the + 4 state.d)The common oxidation states of cerium are + 3 and + 4Correct answer is option 'B'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about Cerium (Z = 58) is an important member of lanthanides. Which of the following statements about cerium is incorrect:a)Cerium IV acts as an oxidizing agent.b)The + 4 oxidation state of cerium is not known in solution.c)The + 3 oxidation state is more stable than the + 4 state.d)The common oxidation states of cerium are + 3 and + 4Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Cerium (Z = 58) is an important member of lanthanides. Which of the following statements about cerium is incorrect:a)Cerium IV acts as an oxidizing agent.b)The + 4 oxidation state of cerium is not known in solution.c)The + 3 oxidation state is more stable than the + 4 state.d)The common oxidation states of cerium are + 3 and + 4Correct answer is option 'B'. Can you explain this answer?.
Solutions for Cerium (Z = 58) is an important member of lanthanides. Which of the following statements about cerium is incorrect:a)Cerium IV acts as an oxidizing agent.b)The + 4 oxidation state of cerium is not known in solution.c)The + 3 oxidation state is more stable than the + 4 state.d)The common oxidation states of cerium are + 3 and + 4Correct answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Chemistry.
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ample number of questions to practice Cerium (Z = 58) is an important member of lanthanides. Which of the following statements about cerium is incorrect:a)Cerium IV acts as an oxidizing agent.b)The + 4 oxidation state of cerium is not known in solution.c)The + 3 oxidation state is more stable than the + 4 state.d)The common oxidation states of cerium are + 3 and + 4Correct answer is option 'B'. Can you explain this answer? tests, examples and also practice Chemistry tests.
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