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Cerium (Z = 58) is an important member of lanthanides. Which of the following statements about cerium is incorrect:
  • a)
    Cerium IV acts as an oxidizing agent.
  • b)
    The + 4 oxidation state of cerium is not known in solution.
  • c)
    The + 3 oxidation state is more stable than the + 4 state.
  • d)
    The common oxidation states of cerium are + 3 and + 4
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
Cerium (Z = 58) is an important member of lanthanides. Which of the fo...
  • The incorrect statement about the Cerium is only the B option.
    B: The +4 oxidation state of cerium is not known in solutions.
    As +4 oxidation state, is common for the Cerium.
  • The correct statements about the Cerium are as follows:
    A: Cerium (IV) acts as an oxidizing agent
    C: The common oxidation state of Cerium are +3 and +4.
    D: The +3 oxidation state of the Cerium is more stable than the +4 oxidation state.
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Most Upvoted Answer
Cerium (Z = 58) is an important member of lanthanides. Which of the fo...
Incorrect statement: The 4 oxidation state of cerium is not known in solution.

Explanation:
Cerium is a member of the lanthanide series and has an atomic number of 58. It has a variety of oxidation states, including +3 and +4. Let's analyze each statement to determine which one is incorrect.

a) Cerium IV acts as an oxidizing agent:
This statement is correct. Cerium can exist in the +4 oxidation state, in which it acts as a strong oxidizing agent. Cerium(IV) compounds, such as cerium(IV) sulfate (Ce(SO4)2), can oxidize other species by donating electrons.

b) The 4 oxidation state of cerium is not known in solution:
This statement is incorrect. Cerium can exist in the +4 oxidation state in solution. Cerium(IV) compounds are often used in redox reactions and as catalysts in organic synthesis. For example, ceric ammonium nitrate [Ce(NH4)2(NO3)6] is a common reagent used for oxidation reactions in organic chemistry.

c) The 3 oxidation state is more stable than the 4 state:
This statement is correct. In general, the +3 oxidation state of cerium is more stable than the +4 oxidation state. This is due to the extra stability provided by the half-filled 4f subshell in the +3 oxidation state. The +3 oxidation state is the most common oxidation state of cerium in its compounds.

d) The common oxidation states of cerium are 3 and 4:
This statement is correct. The most common oxidation states of cerium are +3 and +4. Cerium can also exhibit other oxidation states, such as +2 and +6, but these are less common.

In conclusion, the incorrect statement is b) The 4 oxidation state of cerium is not known in solution. Cerium can exist in the +4 oxidation state in solution and is commonly used in redox reactions and as an oxidizing agent.
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Community Answer
Cerium (Z = 58) is an important member of lanthanides. Which of the fo...
Ans.

Option (b)

The +4 oxidation state of cerium is not known in solutions
+3 and +4 states are shown by Ce in aqueous solution.
+3 and +4 states are shown by Ce in aqueous solution.
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Cerium (Z = 58) is an important member of lanthanides. Which of the following statements about cerium is incorrect:a)Cerium IV acts as an oxidizing agent.b)The + 4 oxidation state of cerium is not known in solution.c)The + 3 oxidation state is more stable than the + 4 state.d)The common oxidation states of cerium are + 3 and + 4Correct answer is option 'B'. Can you explain this answer?
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