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The product acetal is produced by reacting alcohol in the presence of dry HCl with
  • a)
    Acetaldehyde
  • b)
    Ketone
  • c)
    Carboxylic acid
  • d)
    Ether
Correct answer is option 'A'. Can you explain this answer?
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The product acetal is produced by reacting alcohol in the presence of ...
Production of Acetal

Acetal is a functional group in organic chemistry that contains a carbon atom bonded to two -OR groups. It is produced by reacting an alcohol with another compound in the presence of an acid catalyst. The most commonly used alcohol is ethanol, and the acid catalyst is usually dry hydrogen chloride (HCl).

Reaction Mechanism

The reaction mechanism for the production of acetal involves the following steps:

1. Protonation of the alcohol: The acid catalyst (HCl) protonates the alcohol to form an oxonium ion.

2. Nucleophilic attack: The oxonium ion is attacked by the carbonyl group of an aldehyde to form a hemiacetal.

3. Deprotonation: The hemiacetal is deprotonated to form an acetal and a molecule of water.

Reactants and Products

In the production of acetal, the reactants are an alcohol and an aldehyde. The alcohol serves as the nucleophile, while the aldehyde serves as the electrophile. The acid catalyst (HCl) is used to facilitate the reaction.

The product of the reaction is an acetal, which is a stable molecule that is commonly used as a solvent, fuel additive, and plasticizer. Acetal can be further reacted to form more complex molecules, such as acetals and ketals.

Answer

From the above discussion, we can see that the correct option for the question is A, i.e., acetal is produced by reacting alcohol in the presence of dry HCl with acetaldehyde.
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The product acetal is produced by reacting alcohol in the presence of ...
In presence of dry HCl bond between oxygen and hydrogen breaks down and -OR act a nucleophile and attacks on carbon and this attack is takes place twice and acetal is formed.
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Consider a solution of CH3COONH4 which is a salt of weak acid weak base. Theequilibrium involved in the solutions are :If we add these three reactions, then the net reaction isBoth CH3C00- and NH4 get hydrolysed independently and their hydrolysis depends on(i) their initial concentration(ii) the value of Kh which is Since both of the ions were produced from the same salt, their initial concentrations are same . Therefore unless untial the value of Kw/Kaand Kb is same, the degree of hydrolysis of ion cant be same.To explain why we assume that degree of hydrolysis of cation and anion is same, we need to now look at the third reaction i.e., combination of H+ and OH ions. It is obvious that this reaction happens only because one reaction produced H+ ion and the other produced OH ions. We can also note that this reaction causes both the hydrolysis reaction to occur more since their product ions are being consumed. Keep this thing in mind that the equilibrium which has smaller value of equilibrium conxtant is affected more by the common ion effect. For the same reason if for any reason a reaction is made to occur to a greater extent by the consumption of any one of the product ion, the reaction with the smaller value of equilibrium constant tends to get affected more.Therefore we conclude that firstly the hydrolysis of both the ions ocurs more in the presence of each other (due to consumption of the product ions) than in each other is absence. Secondly the hydrolysis of the ion which occurs to a lesser extent (due to smaller value of Kh) is affected more than the one whose Kh is greater. Hence we can see that the degree of hydrolysis of both the ions would be close to each other when they are getting hydrolysed in the presence of each other.Q.In a solution of NaHCO3 , the amphiprotic anion can under ionization to form H+ ion and hydrolysis to from OH ion.To calculat PH, suitable approximation is

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The product acetal is produced by reacting alcohol in the presence of dry HCl witha) Acetaldehyde b) Ketone c) Carboxylic acid d) Ether Correct answer is option 'A'. Can you explain this answer?
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