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Which of the following pairs of solution are expected to be isotonic at the same temperature:
- a)0.1 M urea and 0.1 M NaCl.
- b)100 mL of 1 M urea and 300 mL of 1M glucose.
- c)0.1 M Ca(NO3)2 and 0.1 M Na2SO4
- d)0.1 M NaCl and 0.1 M Na2SO4
Correct answer is option 'B,C'. Can you explain this answer?
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Most Upvoted Answer
Which of the following pairs of solution are expected to be isotonic a...
Check for van't Hoff factor (i)
in (a) urea , i=1 and NaCl, i=2 ; not same
in (b) urea ,i=1 and glucose ,i= 1 ; same
in (c) Ca(NO3)2 , i=3 and Na2So4 , i=3 ; same
in (d) NaCl ,i=2 and Na2So4 , i=3 ;not same
in (a) urea , i=1 and NaCl, i=2 ; not same
in (b) urea ,i=1 and glucose ,i= 1 ; same
in (c) Ca(NO3)2 , i=3 and Na2So4 , i=3 ; same
in (d) NaCl ,i=2 and Na2So4 , i=3 ;not same
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Which of the following pairs of solution are expected to be isotonic a...
Isotonic Solutions
Isotonic solutions are solutions that have the same osmotic pressure across a semipermeable membrane. This means that the concentrations of solutes in the two solutions are equal, resulting in no net movement of water across the membrane.
Given Pairs of Solutions
a) 0.1 M urea and 0.1 M NaCl
b) 100 mL of 1 M urea and 300 mL of 1 M glucose
c) 0.1 M Ca(NO3)2 and 0.1 M Na2SO4
d) 0.1 M NaCl and 0.1 M Na2SO4
Explanation:
Pair a - 0.1 M urea and 0.1 M NaCl:
- Urea and NaCl are both small, non-ionic solutes.
- Urea is a neutral molecule and NaCl dissociates into Na+ and Cl- ions in water.
- Since both solutes have the same concentration, the osmotic pressure will be similar.
- Therefore, this pair of solutions is expected to be isotonic.
Pair b - 100 mL of 1 M urea and 300 mL of 1 M glucose:
- Urea and glucose are both small, non-ionic solutes.
- Urea is a neutral molecule and glucose is also a neutral molecule.
- The concentrations of urea and glucose are different in this case.
- Since the concentrations of solutes are different, the osmotic pressure will also be different.
- Therefore, this pair of solutions is not expected to be isotonic.
Pair c - 0.1 M Ca(NO3)2 and 0.1 M Na2SO4:
- Both Ca(NO3)2 and Na2SO4 dissociate into multiple ions in water.
- Ca(NO3)2 dissociates into Ca2+ and 2NO3- ions, while Na2SO4 dissociates into 2Na+ and SO42- ions.
- The concentrations of ions in both solutions are the same.
- Since the concentrations of ions are the same, the osmotic pressure will be similar.
- Therefore, this pair of solutions is expected to be isotonic.
Pair d - 0.1 M NaCl and 0.1 M Na2SO4:
- Both NaCl and Na2SO4 dissociate into multiple ions in water.
- NaCl dissociates into Na+ and Cl- ions, while Na2SO4 dissociates into 2Na+ and SO42- ions.
- The concentrations of Na+ and Cl- ions in NaCl are the same as the concentrations of Na+ and SO42- ions in Na2SO4.
- Since the concentrations of ions are the same, the osmotic pressure will be similar.
- Therefore, this pair of solutions is expected to be isotonic.
Conclusion:
- The pair of solutions that are expected to be isotonic at the same temperature are option 'B' (100 mL of 1 M urea and 300 mL of 1 M glucose) and option 'C' (0.1 M Ca(NO3)2 and 0.1 M Na2SO4).
Isotonic solutions are solutions that have the same osmotic pressure across a semipermeable membrane. This means that the concentrations of solutes in the two solutions are equal, resulting in no net movement of water across the membrane.
Given Pairs of Solutions
a) 0.1 M urea and 0.1 M NaCl
b) 100 mL of 1 M urea and 300 mL of 1 M glucose
c) 0.1 M Ca(NO3)2 and 0.1 M Na2SO4
d) 0.1 M NaCl and 0.1 M Na2SO4
Explanation:
Pair a - 0.1 M urea and 0.1 M NaCl:
- Urea and NaCl are both small, non-ionic solutes.
- Urea is a neutral molecule and NaCl dissociates into Na+ and Cl- ions in water.
- Since both solutes have the same concentration, the osmotic pressure will be similar.
- Therefore, this pair of solutions is expected to be isotonic.
Pair b - 100 mL of 1 M urea and 300 mL of 1 M glucose:
- Urea and glucose are both small, non-ionic solutes.
- Urea is a neutral molecule and glucose is also a neutral molecule.
- The concentrations of urea and glucose are different in this case.
- Since the concentrations of solutes are different, the osmotic pressure will also be different.
- Therefore, this pair of solutions is not expected to be isotonic.
Pair c - 0.1 M Ca(NO3)2 and 0.1 M Na2SO4:
- Both Ca(NO3)2 and Na2SO4 dissociate into multiple ions in water.
- Ca(NO3)2 dissociates into Ca2+ and 2NO3- ions, while Na2SO4 dissociates into 2Na+ and SO42- ions.
- The concentrations of ions in both solutions are the same.
- Since the concentrations of ions are the same, the osmotic pressure will be similar.
- Therefore, this pair of solutions is expected to be isotonic.
Pair d - 0.1 M NaCl and 0.1 M Na2SO4:
- Both NaCl and Na2SO4 dissociate into multiple ions in water.
- NaCl dissociates into Na+ and Cl- ions, while Na2SO4 dissociates into 2Na+ and SO42- ions.
- The concentrations of Na+ and Cl- ions in NaCl are the same as the concentrations of Na+ and SO42- ions in Na2SO4.
- Since the concentrations of ions are the same, the osmotic pressure will be similar.
- Therefore, this pair of solutions is expected to be isotonic.
Conclusion:
- The pair of solutions that are expected to be isotonic at the same temperature are option 'B' (100 mL of 1 M urea and 300 mL of 1 M glucose) and option 'C' (0.1 M Ca(NO3)2 and 0.1 M Na2SO4).
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Which of the following pairs of solution are expected to be isotonic at the same temperature:a)0.1 M urea and 0.1 M NaCl.b)100 mL of 1 M urea and 300 mL of 1M glucose.c)0.1 M Ca(NO3)2 and 0.1 M Na2SO4d)0.1 M NaCl and 0.1 M Na2SO4Correct answer is option 'B,C'. Can you explain this answer?
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Which of the following pairs of solution are expected to be isotonic at the same temperature:a)0.1 M urea and 0.1 M NaCl.b)100 mL of 1 M urea and 300 mL of 1M glucose.c)0.1 M Ca(NO3)2 and 0.1 M Na2SO4d)0.1 M NaCl and 0.1 M Na2SO4Correct answer is option 'B,C'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about Which of the following pairs of solution are expected to be isotonic at the same temperature:a)0.1 M urea and 0.1 M NaCl.b)100 mL of 1 M urea and 300 mL of 1M glucose.c)0.1 M Ca(NO3)2 and 0.1 M Na2SO4d)0.1 M NaCl and 0.1 M Na2SO4Correct answer is option 'B,C'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Which of the following pairs of solution are expected to be isotonic at the same temperature:a)0.1 M urea and 0.1 M NaCl.b)100 mL of 1 M urea and 300 mL of 1M glucose.c)0.1 M Ca(NO3)2 and 0.1 M Na2SO4d)0.1 M NaCl and 0.1 M Na2SO4Correct answer is option 'B,C'. Can you explain this answer?.
Which of the following pairs of solution are expected to be isotonic at the same temperature:a)0.1 M urea and 0.1 M NaCl.b)100 mL of 1 M urea and 300 mL of 1M glucose.c)0.1 M Ca(NO3)2 and 0.1 M Na2SO4d)0.1 M NaCl and 0.1 M Na2SO4Correct answer is option 'B,C'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about Which of the following pairs of solution are expected to be isotonic at the same temperature:a)0.1 M urea and 0.1 M NaCl.b)100 mL of 1 M urea and 300 mL of 1M glucose.c)0.1 M Ca(NO3)2 and 0.1 M Na2SO4d)0.1 M NaCl and 0.1 M Na2SO4Correct answer is option 'B,C'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Which of the following pairs of solution are expected to be isotonic at the same temperature:a)0.1 M urea and 0.1 M NaCl.b)100 mL of 1 M urea and 300 mL of 1M glucose.c)0.1 M Ca(NO3)2 and 0.1 M Na2SO4d)0.1 M NaCl and 0.1 M Na2SO4Correct answer is option 'B,C'. Can you explain this answer?.
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