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If x and y are integers, is x (y + 1) an even numb
er?
1)xand y are prime numbers.
2)y > 7 ?
a)Exactly one of the statements can answer the question
2)y > 7 ?
a)Exactly one of the statements can answer the question
b)Both statements are required to answer the question
c)Each statement can answer the question individually
d)More information is required as the information provided is insufficient to answer the question
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
If x and y are integers, is x (y + 1) an even numb... moreer?1)xand y ...
1) If x and y are prime numbers, then x(y-1) can be either even or odd. For example, if x is 2 and y is 3, then x(y-1) = 2(3-1) = 4, which is even. However, if x is 3 and y is 5, then x(y-1) = 3(5-1) = 12, which is also even. Therefore, this statement alone is insufficient to determine if x(y-1) is even or odd.
2) If y is odd, then y-1 is even. In this case, x(y-1) will always be even, regardless of the value of x. For example, if y is 5, then y-1 is 4, and x(y-1) will always be even for any integer value of x. Therefore, this statement alone is sufficient to determine that x(y-1) is always even.
Combining both statements, we have conflicting information. Statement 1 tells us that x(y-1) can be either even or odd, while statement 2 tells us that x(y-1) is always even if y is odd. Therefore, the answer is not determinable.
2) If y is odd, then y-1 is even. In this case, x(y-1) will always be even, regardless of the value of x. For example, if y is 5, then y-1 is 4, and x(y-1) will always be even for any integer value of x. Therefore, this statement alone is sufficient to determine that x(y-1) is always even.
Combining both statements, we have conflicting information. Statement 1 tells us that x(y-1) can be either even or odd, while statement 2 tells us that x(y-1) is always even if y is odd. Therefore, the answer is not determinable.
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