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An elevator descends into a mine shaft at the rate of 4m per minute from the ground what Will be it's position after half an hour ? If it begins to descend from 10m above the ground. Find its position after one hour Class 7?
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An elevator descends into a mine shaft at the rate of 4m per minute fr...
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Part 1: Position after half an hour



  • Time taken to descend half an hour = 30 minutes

  • Rate of descent = 4m per minute

  • Distance travelled in half an hour = 4 x 30 = 120m

  • Initial position = 0m above the ground

  • Final position after half an hour = 0 - 120 = -120m below the ground



Therefore, the position of the elevator after half an hour is 120m below the ground.

Part 2: Position after one hour



  • Time taken to descend one hour = 60 minutes

  • Rate of descent = 4m per minute

  • Distance travelled in one hour = 4 x 60 = 240m

  • Initial position = 10m above the ground

  • Final position after one hour = 10 - 240 = -230m below the ground



Therefore, the position of the elevator after one hour is 230m below the ground.
Community Answer
An elevator descends into a mine shaft at the rate of 4m per minute fr...
I am getting confused in this question sorry.... or vese bhi ye to maths ki word problem hai..... if anyone can solve it... then please upload a pic of solution.
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An elevator descends into a mine shaft at the rate of 4m per minute from the ground what Will be it's position after half an hour ? If it begins to descend from 10m above the ground. Find its position after one hour Class 7?
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