IIT JAM Exam > IIT JAM Questions > ?In the proton decoupled 13C and 31P NMR spec...
Start Learning for Free
In the proton decoupled 13C and 31P NMR spectrum of (CH3)3P=O, the number of lines observed respectively are: (a) Two and one (b) One and two (c) Three and One (d) Two and two?
Most Upvoted Answer
?In the proton decoupled 13C and 31P NMR spectrum of (CH3)3P=O, the nu...
Answer:
Introduction:
In NMR spectroscopy, the number of lines observed depends upon the number of chemically distinct nuclei present in the molecule. In the proton decoupled 13C and 31P NMR spectrum of (CH3)3P=O, the number of lines observed can be determined by analyzing the number of chemically distinct carbon and phosphorus atoms present in the molecule.
Explanation:
(CH3)3P=O is a molecule that contains one phosphorus atom and three carbon atoms. The P atom is connected to three methyl (CH3) groups and an oxygen atom.
- 13C NMR Spectrum:
In the proton decoupled 13C NMR spectrum of (CH3)3P=O, two lines are observed. This is because there are two chemically distinct carbon atoms present in the molecule.
- 31P NMR Spectrum:
In the proton decoupled 31P NMR spectrum of (CH3)3P=O, one line is observed. This is because there is only one phosphorus atom present in the molecule.
Conclusion:
Therefore, the correct answer is (a) Two and one. Two lines are observed in the 13C NMR spectrum, and one line is observed in the 31P NMR spectrum of (CH3)3P=O.
Introduction:
In NMR spectroscopy, the number of lines observed depends upon the number of chemically distinct nuclei present in the molecule. In the proton decoupled 13C and 31P NMR spectrum of (CH3)3P=O, the number of lines observed can be determined by analyzing the number of chemically distinct carbon and phosphorus atoms present in the molecule.
Explanation:
(CH3)3P=O is a molecule that contains one phosphorus atom and three carbon atoms. The P atom is connected to three methyl (CH3) groups and an oxygen atom.
- 13C NMR Spectrum:
In the proton decoupled 13C NMR spectrum of (CH3)3P=O, two lines are observed. This is because there are two chemically distinct carbon atoms present in the molecule.
- 31P NMR Spectrum:
In the proton decoupled 31P NMR spectrum of (CH3)3P=O, one line is observed. This is because there is only one phosphorus atom present in the molecule.
Conclusion:
Therefore, the correct answer is (a) Two and one. Two lines are observed in the 13C NMR spectrum, and one line is observed in the 31P NMR spectrum of (CH3)3P=O.
Community Answer
?In the proton decoupled 13C and 31P NMR spectrum of (CH3)3P=O, the nu...
Two and one
|
Explore Courses for IIT JAM exam
|
|
Similar IIT JAM Doubts
?In the proton decoupled 13C and 31P NMR spectrum of (CH3)3P=O, the number of lines observed respectively are: (a) Two and one (b) One and two (c) Three and One (d) Two and two?
Question Description
?In the proton decoupled 13C and 31P NMR spectrum of (CH3)3P=O, the number of lines observed respectively are: (a) Two and one (b) One and two (c) Three and One (d) Two and two? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about ?In the proton decoupled 13C and 31P NMR spectrum of (CH3)3P=O, the number of lines observed respectively are: (a) Two and one (b) One and two (c) Three and One (d) Two and two? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for ?In the proton decoupled 13C and 31P NMR spectrum of (CH3)3P=O, the number of lines observed respectively are: (a) Two and one (b) One and two (c) Three and One (d) Two and two?.
?In the proton decoupled 13C and 31P NMR spectrum of (CH3)3P=O, the number of lines observed respectively are: (a) Two and one (b) One and two (c) Three and One (d) Two and two? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about ?In the proton decoupled 13C and 31P NMR spectrum of (CH3)3P=O, the number of lines observed respectively are: (a) Two and one (b) One and two (c) Three and One (d) Two and two? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for ?In the proton decoupled 13C and 31P NMR spectrum of (CH3)3P=O, the number of lines observed respectively are: (a) Two and one (b) One and two (c) Three and One (d) Two and two?.
Solutions for ?In the proton decoupled 13C and 31P NMR spectrum of (CH3)3P=O, the number of lines observed respectively are: (a) Two and one (b) One and two (c) Three and One (d) Two and two? in English & in Hindi are available as part of our courses for IIT JAM.
Download more important topics, notes, lectures and mock test series for IIT JAM Exam by signing up for free.
Here you can find the meaning of ?In the proton decoupled 13C and 31P NMR spectrum of (CH3)3P=O, the number of lines observed respectively are: (a) Two and one (b) One and two (c) Three and One (d) Two and two? defined & explained in the simplest way possible. Besides giving the explanation of
?In the proton decoupled 13C and 31P NMR spectrum of (CH3)3P=O, the number of lines observed respectively are: (a) Two and one (b) One and two (c) Three and One (d) Two and two?, a detailed solution for ?In the proton decoupled 13C and 31P NMR spectrum of (CH3)3P=O, the number of lines observed respectively are: (a) Two and one (b) One and two (c) Three and One (d) Two and two? has been provided alongside types of ?In the proton decoupled 13C and 31P NMR spectrum of (CH3)3P=O, the number of lines observed respectively are: (a) Two and one (b) One and two (c) Three and One (d) Two and two? theory, EduRev gives you an
ample number of questions to practice ?In the proton decoupled 13C and 31P NMR spectrum of (CH3)3P=O, the number of lines observed respectively are: (a) Two and one (b) One and two (c) Three and One (d) Two and two? tests, examples and also practice IIT JAM tests.
|
|
Explore Courses for IIT JAM exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup