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In the proton decoupled 13C and 31P NMR spectrum of (CH3)3P=O, the number of lines observed respectively are: (a) Two and one (b) One and two (c) Three and One (d) Two and two?
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?In the proton decoupled 13C and 31P NMR spectrum of (CH3)3P=O, the nu...
Answer:

Introduction:
In NMR spectroscopy, the number of lines observed depends upon the number of chemically distinct nuclei present in the molecule. In the proton decoupled 13C and 31P NMR spectrum of (CH3)3P=O, the number of lines observed can be determined by analyzing the number of chemically distinct carbon and phosphorus atoms present in the molecule.

Explanation:
(CH3)3P=O is a molecule that contains one phosphorus atom and three carbon atoms. The P atom is connected to three methyl (CH3) groups and an oxygen atom.

- 13C NMR Spectrum:
In the proton decoupled 13C NMR spectrum of (CH3)3P=O, two lines are observed. This is because there are two chemically distinct carbon atoms present in the molecule.

- 31P NMR Spectrum:
In the proton decoupled 31P NMR spectrum of (CH3)3P=O, one line is observed. This is because there is only one phosphorus atom present in the molecule.

Conclusion:
Therefore, the correct answer is (a) Two and one. Two lines are observed in the 13C NMR spectrum, and one line is observed in the 31P NMR spectrum of (CH3)3P=O.
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?In the proton decoupled 13C and 31P NMR spectrum of (CH3)3P=O, the nu...
Two and one 
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?In the proton decoupled 13C and 31P NMR spectrum of (CH3)3P=O, the number of lines observed respectively are: (a) Two and one (b) One and two (c) Three and One (d) Two and two?
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