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Four distinguishable molecules are distributed in energy level E1 and E2 with degeneracy of2,3 respectively number of microstates with three molecules in energy level E1 and one in energy level 2 is?
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Four distinguishable molecules are distributed in energy level E1 and ...
Solution:

Given:
Number of distinguishable molecules = 4
Energy levels = E1 and E2
Degeneracy of energy level E1 = 2
Degeneracy of energy level E2 = 3

To find:
Number of microstates with three molecules in energy level E1 and one in energy level E2.

Explanation:

Total number of microstates for a system with N molecules is given by the formula:

Ω = (N+n-1)! / n!(N-1)!

Where N is the total number of molecules and n is the number of energy levels.

Number of microstates with three molecules in energy level E1 and one in energy level E2 can be calculated as follows:

Number of ways to choose three molecules from four molecules to fill the energy level E1= 4C3 = 4

Number of ways to choose one molecule from four molecules to fill the energy level E2 = 4C1 = 4

Number of microstates for three molecules in energy level E1 = 2x2x2 = 8

Number of microstates for one molecule in energy level E2 = 3

Number of microstates for the system with three molecules in energy level E1 and one in energy level E2 can be calculated as follows:

Ω = (N+n-1)! / n!(N-1)!
Ω = (4+2-1)! / 2!(4-1)!
Ω = (5)! / 2!(3)!
Ω = 10

Therefore, the number of microstates with three molecules in energy level E1 and one in energy level E2 is 8x3x10 = 240.

Conclusion:

The number of microstates with three molecules in energy level E1 and one in energy level E2 is 240.
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Four distinguishable molecules are distributed in energy level E1 and ...
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Four distinguishable molecules are distributed in energy level E1 and E2 with degeneracy of2,3 respectively number of microstates with three molecules in energy level E1 and one in energy level 2 is?
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