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Anyone solve plz.zeroes of cubic polynomial X3-6X2 +3X+ 10 are of form a,a b,a-b . Find a and b and zeroes of polynomial also . where a and b are real values ?
Most Upvoted Answer
Anyone solve plz.zeroes of cubic polynomial X3-6X2 +3X+ 10 are of form...
Alpha = a , beeta = a +b & gamma = a - b
alpha + beeta + gamma = -b/a
a + a + b +a - b = -(-6)
3a = 6
a = 2
alpha × beeta × gamma = -d/a
a (a -b) (a +b) = -10
2 (a^2 - b^2) = -10
2^2 -b^2 = -5
4 - b^2 = -5
b^2 = 9
b = 3
Community Answer
Anyone solve plz.zeroes of cubic polynomial X3-6X2 +3X+ 10 are of form...
Analysis of the Cubic Polynomial X^3 - 6X^2 + 3X + 10:
- Finding the Zeroes:
To find the zeroes of the cubic polynomial, we look for values of x where the polynomial equals zero. The zeroes are the values of x for which the polynomial factors into (x - a)(x - b)(x - c) = 0.
- Given Form of Zeroes:
The zeroes of the polynomial are of the form a, a-b, and a+b.
- Let's Assume the Zeroes:
Let's assume that the zeroes of the polynomial are a, a-b, and a+b.
- Sum and Product of Zeroes:
The sum of the zeroes of a cubic polynomial is given by -(-6)/1 = 6 and the product of the zeroes is 10.
- Equation Formation:
Using the sum and product of zeroes, we can form the following equations:
a + (a - b) + (a + b) = 6
a(a - b)(a + b) = 10
- Solving the Equations:
By solving the equations simultaneously, we can find the values of a and b. Then, we can substitute these values to find the zeroes of the polynomial.
- Conclusion:
By following the steps mentioned above, we can determine the values of a and b and find the zeroes of the given cubic polynomial X^3 - 6X^2 + 3X + 10.
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Anyone solve plz.zeroes of cubic polynomial X3-6X2 +3X+ 10 are of form a,a b,a-b . Find a and b and zeroes of polynomial also . where a and b are real values ?
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