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A number between 10 and100 is five times the sum of its digits. If 9 be added to it the digits are reversed,find the number?
Most Upvoted Answer
A number between 10 and100 is five times the sum of its digits. If 9 b...
Analysis:
The number we are looking for is between 10 and 100, which means it is a two-digit number. Let's represent the number as 10x + y, where x is the digit in the tens place and y is the digit in the ones place.

Given Conditions:
1. 10x + y = 5(x + y)
2. 10x + y + 9 = 10y + x

Solving the Equations:
From the first equation:
10x + y = 5x + 5y
=> 5x = 4y
=> y = (5/4)x
Substitute y in terms of x into the second equation:
10x + (5/4)x + 9 = 10(5/4)x + x
=> 10x + 1.25x + 9 = 12.5x + x
=> 11.25x + 9 = 13.5x
=> 2.25x = 9
=> x = 4
Substitute x = 4 back into y = (5/4)x:
y = (5/4) * 4
y = 5

Final Answer:
The number is 10x + y = 10 * 4 + 5 = 45. So, the number is 45.
Community Answer
A number between 10 and100 is five times the sum of its digits. If 9 b...
45
and add 9 in this number u will get 54 and reverses the
is 45
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A number between 10 and100 is five times the sum of its digits. If 9 be added to it the digits are reversed,find the number?
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