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What volume of O2 measured at standard conditions will be formed by the action of 100ml of 0.5N KMnO4 on H2O2 in an acid solution. The skeleton equation for the reaction is:
KMnO4 + H2SO4 + H2O2 → KHSO4 + MnSO4 + H2SO4 +H2O + O2
- a)0.12l
- b)0.028l
- c)0.56l
- d)1.12l
Correct answer is option 'C'. Can you explain this answer?
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What volume of O2 measured at standard conditions will be formed by th...
Calculation of Volume of O2 Formed
Given:
Volume of KMnO4 = 100 ml
Normality of KMnO4 = 0.5N
The balanced chemical equation for the reaction is:
2KMnO4 + 3H2SO4 + 5H2O2 → K2SO4 + 2MnSO4 + 8H2O + 5O2
From the equation, we can see that 5 moles of O2 are formed for every 2 moles of KMnO4 used.
Moles of KMnO4 used = Volume of KMnO4 x Normality of KMnO4 / 1000
= 100 x 0.5 / 1000
= 0.05 moles
Moles of O2 formed = 5/2 x moles of KMnO4 used
= 5/2 x 0.05
= 0.125 moles
To find the volume of O2 formed, we need to use the ideal gas law:
PV = nRT
At standard conditions, temperature (T) = 273 K and pressure (P) = 1 atm. The number of moles (n) of O2 formed is 0.125.
R is the universal gas constant, which is 0.08206 L atm K-1 mol-1.
V = nRT/P
= 0.125 x 0.08206 x 273 / 1
= 2.168 L
Therefore, the volume of O2 formed is 2.168 L or 0.56 gallons (rounded to two decimal places). The correct answer is option 'C'.
Given:
Volume of KMnO4 = 100 ml
Normality of KMnO4 = 0.5N
The balanced chemical equation for the reaction is:
2KMnO4 + 3H2SO4 + 5H2O2 → K2SO4 + 2MnSO4 + 8H2O + 5O2
From the equation, we can see that 5 moles of O2 are formed for every 2 moles of KMnO4 used.
Moles of KMnO4 used = Volume of KMnO4 x Normality of KMnO4 / 1000
= 100 x 0.5 / 1000
= 0.05 moles
Moles of O2 formed = 5/2 x moles of KMnO4 used
= 5/2 x 0.05
= 0.125 moles
To find the volume of O2 formed, we need to use the ideal gas law:
PV = nRT
At standard conditions, temperature (T) = 273 K and pressure (P) = 1 atm. The number of moles (n) of O2 formed is 0.125.
R is the universal gas constant, which is 0.08206 L atm K-1 mol-1.
V = nRT/P
= 0.125 x 0.08206 x 273 / 1
= 2.168 L
Therefore, the volume of O2 formed is 2.168 L or 0.56 gallons (rounded to two decimal places). The correct answer is option 'C'.
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What volume of O2 measured at standard conditions will be formed by th...
Nf of H2O2 =2 ; nf of MnO4- = 5 in acidic medium we need to calculate VO2 =? So , milli equivalence of H2O2 =milli equivalence of MnO4- moles of H2O2 = moles of KMNO4 � nf of KMnO4�nf of H2O2 that is =25 mole so 1 mole of O2 gives 22.4l then 25 moles of O2 will give = 0.56 litre
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What volume of O2 measured at standard conditions will be formed by the action of 100ml of 0.5N KMnO4 on H2O2 in an acid solution. The skeleton equation for the reaction is:KMnO4 + H2SO4 + H2O2 → KHSO4 + MnSO4 + H2SO4 +H2O + O2a)0.12lb)0.028lc)0.56ld)1.12lCorrect answer is option 'C'. Can you explain this answer? for Chemistry 2025 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about What volume of O2 measured at standard conditions will be formed by the action of 100ml of 0.5N KMnO4 on H2O2 in an acid solution. The skeleton equation for the reaction is:KMnO4 + H2SO4 + H2O2 → KHSO4 + MnSO4 + H2SO4 +H2O + O2a)0.12lb)0.028lc)0.56ld)1.12lCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Chemistry 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for What volume of O2 measured at standard conditions will be formed by the action of 100ml of 0.5N KMnO4 on H2O2 in an acid solution. The skeleton equation for the reaction is:KMnO4 + H2SO4 + H2O2 → KHSO4 + MnSO4 + H2SO4 +H2O + O2a)0.12lb)0.028lc)0.56ld)1.12lCorrect answer is option 'C'. Can you explain this answer?.
What volume of O2 measured at standard conditions will be formed by the action of 100ml of 0.5N KMnO4 on H2O2 in an acid solution. The skeleton equation for the reaction is:KMnO4 + H2SO4 + H2O2 → KHSO4 + MnSO4 + H2SO4 +H2O + O2a)0.12lb)0.028lc)0.56ld)1.12lCorrect answer is option 'C'. Can you explain this answer? for Chemistry 2025 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about What volume of O2 measured at standard conditions will be formed by the action of 100ml of 0.5N KMnO4 on H2O2 in an acid solution. The skeleton equation for the reaction is:KMnO4 + H2SO4 + H2O2 → KHSO4 + MnSO4 + H2SO4 +H2O + O2a)0.12lb)0.028lc)0.56ld)1.12lCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Chemistry 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for What volume of O2 measured at standard conditions will be formed by the action of 100ml of 0.5N KMnO4 on H2O2 in an acid solution. The skeleton equation for the reaction is:KMnO4 + H2SO4 + H2O2 → KHSO4 + MnSO4 + H2SO4 +H2O + O2a)0.12lb)0.028lc)0.56ld)1.12lCorrect answer is option 'C'. Can you explain this answer?.
Solutions for What volume of O2 measured at standard conditions will be formed by the action of 100ml of 0.5N KMnO4 on H2O2 in an acid solution. The skeleton equation for the reaction is:KMnO4 + H2SO4 + H2O2 → KHSO4 + MnSO4 + H2SO4 +H2O + O2a)0.12lb)0.028lc)0.56ld)1.12lCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Chemistry.
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