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The area of four walls of the room is
- a)2 (lb + bh + hl)
- b)2l (h + b)
- c)2 (lb x bh x hl)
- d)2h (l + b)
Correct answer is option 'D'. Can you explain this answer?
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Verified Answer
The area of four walls of the room is a)2 (lb + bh + hl)b)2l (h + b)c)...
Since we have area of wall as b*h and h*l .So area of 4 walls is 2h*b+2h*l=2h(b+l)
Most Upvoted Answer
The area of four walls of the room is a)2 (lb + bh + hl)b)2l (h + b)c)...
Explanation:
The area of four walls of a rectangular room can be found by adding the areas of all four walls.
Let's consider a rectangular room with dimensions l (length), b (breadth) and h (height).
1. Finding the area of the first wall:
The first wall has a length of l and a height of h. So, its area is:
Area of first wall = l x h
2. Finding the area of the second wall:
The second wall has a length of l and a height of h. So, its area is:
Area of second wall = l x h
3. Finding the area of the third wall:
The third wall has a length of b and a height of h. So, its area is:
Area of third wall = b x h
4. Finding the area of the fourth wall:
The fourth wall has a length of b and a height of h. So, its area is:
Area of fourth wall = b x h
5. Adding all the areas to get the total area:
Total area of four walls = Area of first wall + Area of second wall + Area of third wall + Area of fourth wall
= l x h + l x h + b x h + b x h
= 2lh + 2bh
= 2h(l + b)
Therefore, the correct answer is option 'D', which is 2h(l + b).
The area of four walls of a rectangular room can be found by adding the areas of all four walls.
Let's consider a rectangular room with dimensions l (length), b (breadth) and h (height).
1. Finding the area of the first wall:
The first wall has a length of l and a height of h. So, its area is:
Area of first wall = l x h
2. Finding the area of the second wall:
The second wall has a length of l and a height of h. So, its area is:
Area of second wall = l x h
3. Finding the area of the third wall:
The third wall has a length of b and a height of h. So, its area is:
Area of third wall = b x h
4. Finding the area of the fourth wall:
The fourth wall has a length of b and a height of h. So, its area is:
Area of fourth wall = b x h
5. Adding all the areas to get the total area:
Total area of four walls = Area of first wall + Area of second wall + Area of third wall + Area of fourth wall
= l x h + l x h + b x h + b x h
= 2lh + 2bh
= 2h(l + b)
Therefore, the correct answer is option 'D', which is 2h(l + b).
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The area of four walls of the room is a)2 (lb + bh + hl)b)2l (h + b)c)...
2 (l+b) h . .. ... ....
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The area of four walls of the room is a)2 (lb + bh + hl)b)2l (h + b)c)2 (lb x bh x hl)d)2h (l + b)Correct answer is option 'D'. Can you explain this answer?
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