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A single phase half bridge inverter is feeding power into a load of resistance 20 Ω, dc input to the inverter is 500V. Then the power factor is_____
Correct answer is between '0.98,1'. Can you explain this answer?
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A single phase half bridge inverter is feeding power into a load of re...
RMS value of output voltage is, 
RMS value of load current is,
RMS value of load current is,
Power delivered, 
Power factor, cosϕ = P/VI = 0.99
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A single phase half bridge inverter is feeding power into a load of re...
To calculate the power being delivered to the load, we need to know the voltage being applied by the inverter.
Assuming the voltage being applied by the inverter is V, the power delivered to the load can be calculated using the formula:
Power = (V^2) / R
where R is the resistance of the load.
In this case, the resistance of the load is given as 20 ohms.
So, the power delivered to the load is:
Power = (V^2) / 20
Please provide the value of V to calculate the power.
Assuming the voltage being applied by the inverter is V, the power delivered to the load can be calculated using the formula:
Power = (V^2) / R
where R is the resistance of the load.
In this case, the resistance of the load is given as 20 ohms.
So, the power delivered to the load is:
Power = (V^2) / 20
Please provide the value of V to calculate the power.
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A single phase half bridge inverter is feeding power into a load of resistance 20 Ω, dc input to the inverter is 500V. Then the power factor is_____Correct answer is between '0.98,1'. Can you explain this answer?
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