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It is required to operate 200 A SCR in parallel with 300 A SCR with their respective ON – State voltage drop of 2 V and 1.2 V. calculate the value of resistance to be inserted in series with each SCR so that they share the total load of 500 A in proportional to their current ratings – (in mΩ)
Correct answer is '8'. Can you explain this answer?
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It is required to operate 200 A SCR in parallel with 300 A SCR with th...
Dynamic resistance of SCR with 200 A
= 2/200 = 0.01Ω = 10 mΩ
Dynamic resistance of SCR with 300 A
Dynamic resistance of SCR with 300 A
= 1.2/300 = 0.004Ω = 4 mΩ
Let Rs be the resistance inserted in series with each SCR.
Let Rs be the resistance inserted in series with each SCR.
Current shared by SCR1 = 500 
Current shared by SCR2 = 500
⇒ 12 + 3 Rs = 20 + 2Rs
Current shared by SCR2 = 500
⇒ 12 + 3 Rs = 20 + 2Rs
⇒ Rs = 8 m Ω
Most Upvoted Answer
It is required to operate 200 A SCR in parallel with 300 A SCR with th...
And OFF state parameters given as follows:
For 200 A SCR:
- ON-State Voltage Drop (Von) = 2.5 V
- Holding Current (IH) = 50 mA
- Peak Surge Current (ITSM) = 1.5 kA
For 300 A SCR:
- ON-State Voltage Drop (Von) = 2.8 V
- Holding Current (IH) = 70 mA
- Peak Surge Current (ITSM) = 2 kA
To operate the SCRs in parallel, we need to make sure that their parameters are compatible and within the specified limits. Let's check each parameter:
1. ON-State Voltage Drop (Von):
- Since the ON-State Voltage Drop for the two SCRs is different, we need to ensure that the SCR with the higher voltage drop is not subjected to a voltage drop lower than its specified value. In this case, the 300 A SCR has a higher Von value of 2.8 V compared to the 200 A SCR's 2.5 V. So, we need to make sure that the load voltage is not lower than 2.8 V.
2. Holding Current (IH):
- The holding current is the minimum current required to keep the SCR in the ON state once triggered. Since the IH for the 300 A SCR is higher (70 mA) than that of the 200 A SCR (50 mA), we need to ensure that the load current is higher than 70 mA to keep both SCRs conducting.
3. Peak Surge Current (ITSM):
- The peak surge current is the maximum current that the SCR can handle for a short duration. In this case, the 300 A SCR has a higher ITSM value of 2 kA compared to the 200 A SCR's 1.5 kA. So, we need to ensure that the load current does not exceed 1.5 kA to prevent overloading the 200 A SCR.
Based on these parameters, we need to choose a load current that satisfies the requirements of both SCRs. Let's assume the load current is IL.
For the 200 A SCR:
IL ≤ 200 A
For the 300 A SCR:
IL ≤ 300 A
IL > 70 mA (IH)
To satisfy both SCRs, the load current should be within 70 mA to 200 A.
It is important to note that operating SCRs in parallel can be challenging due to differences in parameters, such as voltage drops and holding currents. It is recommended to use SCRs of the same type and specifications to ensure proper parallel operation.
For 200 A SCR:
- ON-State Voltage Drop (Von) = 2.5 V
- Holding Current (IH) = 50 mA
- Peak Surge Current (ITSM) = 1.5 kA
For 300 A SCR:
- ON-State Voltage Drop (Von) = 2.8 V
- Holding Current (IH) = 70 mA
- Peak Surge Current (ITSM) = 2 kA
To operate the SCRs in parallel, we need to make sure that their parameters are compatible and within the specified limits. Let's check each parameter:
1. ON-State Voltage Drop (Von):
- Since the ON-State Voltage Drop for the two SCRs is different, we need to ensure that the SCR with the higher voltage drop is not subjected to a voltage drop lower than its specified value. In this case, the 300 A SCR has a higher Von value of 2.8 V compared to the 200 A SCR's 2.5 V. So, we need to make sure that the load voltage is not lower than 2.8 V.
2. Holding Current (IH):
- The holding current is the minimum current required to keep the SCR in the ON state once triggered. Since the IH for the 300 A SCR is higher (70 mA) than that of the 200 A SCR (50 mA), we need to ensure that the load current is higher than 70 mA to keep both SCRs conducting.
3. Peak Surge Current (ITSM):
- The peak surge current is the maximum current that the SCR can handle for a short duration. In this case, the 300 A SCR has a higher ITSM value of 2 kA compared to the 200 A SCR's 1.5 kA. So, we need to ensure that the load current does not exceed 1.5 kA to prevent overloading the 200 A SCR.
Based on these parameters, we need to choose a load current that satisfies the requirements of both SCRs. Let's assume the load current is IL.
For the 200 A SCR:
IL ≤ 200 A
For the 300 A SCR:
IL ≤ 300 A
IL > 70 mA (IH)
To satisfy both SCRs, the load current should be within 70 mA to 200 A.
It is important to note that operating SCRs in parallel can be challenging due to differences in parameters, such as voltage drops and holding currents. It is recommended to use SCRs of the same type and specifications to ensure proper parallel operation.
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It is required to operate 200 A SCR in parallel with 300 A SCR with their respective ON – State voltage drop of 2 V and 1.2 V. calculate the value of resistance to be inserted in series with each SCR so that they share the total load of 500 A in proportional to their current ratings – (in mΩ)Correct answer is '8'. Can you explain this answer?
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It is required to operate 200 A SCR in parallel with 300 A SCR with their respective ON – State voltage drop of 2 V and 1.2 V. calculate the value of resistance to be inserted in series with each SCR so that they share the total load of 500 A in proportional to their current ratings – (in mΩ)Correct answer is '8'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about It is required to operate 200 A SCR in parallel with 300 A SCR with their respective ON – State voltage drop of 2 V and 1.2 V. calculate the value of resistance to be inserted in series with each SCR so that they share the total load of 500 A in proportional to their current ratings – (in mΩ)Correct answer is '8'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for It is required to operate 200 A SCR in parallel with 300 A SCR with their respective ON – State voltage drop of 2 V and 1.2 V. calculate the value of resistance to be inserted in series with each SCR so that they share the total load of 500 A in proportional to their current ratings – (in mΩ)Correct answer is '8'. Can you explain this answer?.
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