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Two single-core power cables have total conductor resistances of 0.7 Q and 0.5 Q, respectively, and their insulation resistances (between core and sheath) are 600 MQ and 900 M£1 respectively, When the two cables are joined in series, the ratio of insulation resistance to conductor resistance i s _______ x 106.
    Correct answer is '300'. Can you explain this answer?
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    Two single-core power cables have total conductor resistances of 0.7 Q...
    Q, respectively. The cables are connected in parallel. To calculate the total resistance, we can use the formula for resistors in parallel:

    1/RTotal = 1/R1 + 1/R2

    Where RTotal is the total resistance, R1 is the resistance of the first cable, and R2 is the resistance of the second cable.

    Plugging in the given values:

    1/RTotal = 1/0.7 + 1/0.5

    Simplifying:

    1/RTotal = (1/0.7 + 1/0.5) / (0.7 * 0.5)

    1/RTotal = (1.4286 + 2) / 0.35

    1/RTotal = 3.4286 / 0.35

    1/RTotal = 9.796

    RTotal = 1 / 9.796

    RTotal ≈ 0.102 Q

    Therefore, the total resistance of the parallel combination of the two cables is approximately 0.102 Q.
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    Two single-core power cables have total conductor resistances of 0.7 Q and 0.5 Q, respectively, and their insulation resistances (between core and sheath) are 600 MQ and 900 M£1 respectively, When the two cables are joined in series, the ratio of insulation resistance to conductor resistance i s _______ x 106.Correct answer is '300'. Can you explain this answer?
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