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If the head loss due to sudden enlargement of water main from 180 mm to 460 mm diameter is 0.17 cm of mercury. The flow rate in the water main is ________ l/s. Take relative density of mercury as 13.6.
Correct answer is between '19.8,20.8'. Can you explain this answer?
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If the head loss due to sudden enlargement of water main from 180 mm t...
Head loss due to sudden enlargement is given by:
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If the head loss due to sudden enlargement of water main from 180 mm t...
Head Loss Calculation
--------------------------
To calculate the flow rate in the water main, we need to first determine the head loss due to the sudden enlargement of the water main. The head loss can be calculated using the following equation:
Δh = (V²/2g) * (K₁² - K₂²)
where:
Δh = head loss (in meters)
V = velocity of flow (in m/s)
g = acceleration due to gravity (9.81 m/s²)
K₁ = coefficient of contraction for the smaller diameter (180 mm)
K₂ = coefficient of contraction for the larger diameter (460 mm)
The head loss is given as 0.17 cm of mercury. To convert this to meters, we can use the relative density of mercury, which is 13.6. Thus, 0.17 cm of mercury is equivalent to 0.17 * (13.6 / 100) meters.
Now, let's solve the equation for the head loss:
0.17 * (13.6 / 100) = (V²/2 * 9.81) * (K₁² - K₂²)
We can simplify this equation by assuming that both K₁ and K₂ are equal to the coefficient of velocity (Cv), which is approximately 0.98 for sudden enlargements. Therefore, we have:
0.17 * (13.6 / 100) = (V²/2 * 9.81) * (0.98² - 0.98²)
Simplifying further:
0.17 * (13.6 / 100) = (V²/2 * 9.81) * 0
Since the term (0.98² - 0.98²) equals zero, the equation becomes:
0.17 * (13.6 / 100) = 0
This equation is not possible to solve because it implies that 0.23 (0.17 * 13.6 / 100) is equal to zero. Therefore, there seems to be an error in the given data or calculation.
Conclusion
--------------------------
Based on the given data, it is not possible to determine the flow rate in the water main. The equation for head loss does not yield a valid solution, suggesting an error in the problem statement or calculation.
--------------------------
To calculate the flow rate in the water main, we need to first determine the head loss due to the sudden enlargement of the water main. The head loss can be calculated using the following equation:
Δh = (V²/2g) * (K₁² - K₂²)
where:
Δh = head loss (in meters)
V = velocity of flow (in m/s)
g = acceleration due to gravity (9.81 m/s²)
K₁ = coefficient of contraction for the smaller diameter (180 mm)
K₂ = coefficient of contraction for the larger diameter (460 mm)
The head loss is given as 0.17 cm of mercury. To convert this to meters, we can use the relative density of mercury, which is 13.6. Thus, 0.17 cm of mercury is equivalent to 0.17 * (13.6 / 100) meters.
Now, let's solve the equation for the head loss:
0.17 * (13.6 / 100) = (V²/2 * 9.81) * (K₁² - K₂²)
We can simplify this equation by assuming that both K₁ and K₂ are equal to the coefficient of velocity (Cv), which is approximately 0.98 for sudden enlargements. Therefore, we have:
0.17 * (13.6 / 100) = (V²/2 * 9.81) * (0.98² - 0.98²)
Simplifying further:
0.17 * (13.6 / 100) = (V²/2 * 9.81) * 0
Since the term (0.98² - 0.98²) equals zero, the equation becomes:
0.17 * (13.6 / 100) = 0
This equation is not possible to solve because it implies that 0.23 (0.17 * 13.6 / 100) is equal to zero. Therefore, there seems to be an error in the given data or calculation.
Conclusion
--------------------------
Based on the given data, it is not possible to determine the flow rate in the water main. The equation for head loss does not yield a valid solution, suggesting an error in the problem statement or calculation.
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If the head loss due to sudden enlargement of water main from 180 mm to 460 mm diameter is 0.17 cm of mercury. The flow rate in the water main is ________ l/s. Take relative density of mercury as 13.6.Correct answer is between '19.8,20.8'. Can you explain this answer?
Question Description
If the head loss due to sudden enlargement of water main from 180 mm to 460 mm diameter is 0.17 cm of mercury. The flow rate in the water main is ________ l/s. Take relative density of mercury as 13.6.Correct answer is between '19.8,20.8'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about If the head loss due to sudden enlargement of water main from 180 mm to 460 mm diameter is 0.17 cm of mercury. The flow rate in the water main is ________ l/s. Take relative density of mercury as 13.6.Correct answer is between '19.8,20.8'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If the head loss due to sudden enlargement of water main from 180 mm to 460 mm diameter is 0.17 cm of mercury. The flow rate in the water main is ________ l/s. Take relative density of mercury as 13.6.Correct answer is between '19.8,20.8'. Can you explain this answer?.
If the head loss due to sudden enlargement of water main from 180 mm to 460 mm diameter is 0.17 cm of mercury. The flow rate in the water main is ________ l/s. Take relative density of mercury as 13.6.Correct answer is between '19.8,20.8'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about If the head loss due to sudden enlargement of water main from 180 mm to 460 mm diameter is 0.17 cm of mercury. The flow rate in the water main is ________ l/s. Take relative density of mercury as 13.6.Correct answer is between '19.8,20.8'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If the head loss due to sudden enlargement of water main from 180 mm to 460 mm diameter is 0.17 cm of mercury. The flow rate in the water main is ________ l/s. Take relative density of mercury as 13.6.Correct answer is between '19.8,20.8'. Can you explain this answer?.
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