Consider the following statements P and Q:(Q): Let S be a diagonalizab...
A matrix is said to be singular, if determinant of that matrix is zero.
= 1 (18 – 12) - 1 (9 – 4) + 1 (3 – 2)
= 6 – 5 + 1 = 2 ≠ 0
M is non singular
(Q) A matrix can be diagonalizable when it has distinct eigen values
S is a diagonalizable matrix. Hence, has distinct eigen values.
Let S be a 3 × 3 matrix and the eigen values of s are λ1, λ2, λ3
Given that, S + 5T = I
From the properties of Eigen values,
(a) If λ1 is an eigen value of matrix A, then -λ1 will be on eigen value of matrix -A.
(b) If λ1 is an eigen value of matrix A, then (λ1 + 1) will be an eigen value of matrix (A + I)
(c) If λ1 is an eigen value of matrix A, then -λ1 will be an eigen value of matrix where K is a scalar.
From the above properties, eigen values of T are,
As λ
1, λ
2, λ
3 are distinct values,
will be distinct.
Hence, matrix T is diagonalizable
So, only Q is true.