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A Lissajous pattern on the oscilloscope is stationary having 8 vertical maximum values and 6 horizontal maximum values. The frequency of vertical input of the frequency of horizontal input if the frequency of horizontal input is 1800 kHz is – (in kHz)
    Correct answer is '1350'. Can you explain this answer?
    Verified Answer
    A Lissajous pattern on the oscilloscope is stationary having 8 vertica...
    Given that,
    Horizontal frequency (fH) = 1800 kHz
    Number of vertical tangencies (Nv) = 8
    Number of horizontal tangencies (NH) = 6
    We know that,
    fHNH = fvNv
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    Most Upvoted Answer
    A Lissajous pattern on the oscilloscope is stationary having 8 vertica...
    1500 kHz.

    The ratio of the frequencies of the vertical and horizontal inputs is given by the formula:

    f_v/f_h = n_v/n_h

    where f_v and f_h are the frequencies of the vertical and horizontal inputs, and n_v and n_h are the number of maximum values in the vertical and horizontal directions, respectively.

    In this case, n_v = 8 and n_h = 6, and f_h = 1800 kHz. Substituting these values into the formula, we get:

    f_v/1800 kHz = 8/6

    Simplifying, we get:

    f_v = (8/6) x 1800 kHz = 2400 kHz/2 = 1200 kHz

    Therefore, the frequency of the vertical input is 1200 kHz, and the ratio of the frequencies is:

    f_v/f_h = 1200 kHz/1800 kHz = 2/3

    Alternatively, we can use the fact that the Lissajous pattern is stationary to determine the frequency ratio. Since the pattern has 8 vertical maximum values and 6 horizontal maximum values, it completes 8 cycles in the vertical direction for every 6 cycles in the horizontal direction. Therefore, the frequency ratio is:

    f_v/f_h = 8/6 = 4/3

    Multiplying both sides by f_h, we get:

    f_v = (4/3) x 1800 kHz = 2400 kHz/2 = 1200 kHz

    which confirms our previous result.
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    A Lissajous pattern on the oscilloscope is stationary having 8 vertical maximum values and 6 horizontal maximum values. The frequency of vertical input of the frequency of horizontal input if the frequency of horizontal input is 1800 kHz is – (in kHz)Correct answer is '1350'. Can you explain this answer?
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