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Find the point at which maximum value of f(x) = 2x3−3x2 occurs in interval [-2, 2]?
  • a)
    1
  • b)
    0
  • c)
    -1
  • d)
    2
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
Find the point at which maximum value off(x) = 2x3−3x2 occurs in...
f(x) = 2x3 − 3x2
f′(x) = 6x2 − 6x
f′′(x) = 12x − 6
f′(x) = 6x2 − 6x = 0
6x (x−1) = 0
x = 0 or x = 1
Now check f(x) at x = 0, x = 1 and the end points of given interval since at end point tangent cannot be drawn so, above concept cannot be used to find maximum or minimum value for end points.
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