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The equilibrium constant for the reaction: at 200 K is 4 x10-4. In presence of catalyst, equilibrium is attained 5 times faster, then value of equilibrium constant at 200 K in presence of catayst will bea)2x10-3 b)20x10-3 c)4x10-4 d)4x10-3Correct answer is option 'C'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about The equilibrium constant for the reaction: at 200 K is 4 x10-4. In presence of catalyst, equilibrium is attained 5 times faster, then value of equilibrium constant at 200 K in presence of catayst will bea)2x10-3 b)20x10-3 c)4x10-4 d)4x10-3Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The equilibrium constant for the reaction: at 200 K is 4 x10-4. In presence of catalyst, equilibrium is attained 5 times faster, then value of equilibrium constant at 200 K in presence of catayst will bea)2x10-3 b)20x10-3 c)4x10-4 d)4x10-3Correct answer is option 'C'. Can you explain this answer?.

Solutions for The equilibrium constant for the reaction: at 200 K is 4 x10-4. In presence of catalyst, equilibrium is attained 5 times faster, then value of equilibrium constant at 200 K in presence of catayst will bea)2x10-3 b)20x10-3 c)4x10-4 d)4x10-3Correct answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12. Download more important topics, notes, lectures and mock test series for Class 12 Exam by signing up for free.

Here you can find the meaning of The equilibrium constant for the reaction: at 200 K is 4 x10-4. In presence of catalyst, equilibrium is attained 5 times faster, then value of equilibrium constant at 200 K in presence of catayst will bea)2x10-3 b)20x10-3 c)4x10-4 d)4x10-3Correct answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of The equilibrium constant for the reaction: at 200 K is 4 x10-4. In presence of catalyst, equilibrium is attained 5 times faster, then value of equilibrium constant at 200 K in presence of catayst will bea)2x10-3 b)20x10-3 c)4x10-4 d)4x10-3Correct answer is option 'C'. Can you explain this answer?, a detailed solution for The equilibrium constant for the reaction: at 200 K is 4 x10-4. In presence of catalyst, equilibrium is attained 5 times faster, then value of equilibrium constant at 200 K in presence of catayst will bea)2x10-3 b)20x10-3 c)4x10-4 d)4x10-3Correct answer is option 'C'. Can you explain this answer? has been provided alongside types of The equilibrium constant for the reaction: at 200 K is 4 x10-4. In presence of catalyst, equilibrium is attained 5 times faster, then value of equilibrium constant at 200 K in presence of catayst will bea)2x10-3 b)20x10-3 c)4x10-4 d)4x10-3Correct answer is option 'C'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice The equilibrium constant for the reaction: at 200 K is 4 x10-4. In presence of catalyst, equilibrium is attained 5 times faster, then value of equilibrium constant at 200 K in presence of catayst will bea)2x10-3 b)20x10-3 c)4x10-4 d)4x10-3Correct answer is option 'C'. Can you explain this answer? tests, examples and also practice Class 12 tests.