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A length of cable was tested for insulation resistance using loss of charge method. A capacitance formed by sheath of cable of 300 PF is found to have drop in voltage from 300 V to 100 V in 120 seconds. Calculate the insulation resistance of the cable in MΩ 
  • a)
    0.367 × 106 MΩ
  • b)
    0.12 × 106 MΩ
  • c)
    0.45 MΩ 
  • d)
    0.45 × 106 MΩ
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
A length of cable was tested for insulation resistance using loss of c...
Given that = C = 300 pF
V1 = 300 V
V2 = 100 V
t = 120 S
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Most Upvoted Answer
A length of cable was tested for insulation resistance using loss of c...
To calculate the insulation resistance of the cable, we can use the formula:

Insulation Resistance (R) = (Time (T) * Capacitance (C)) / (Voltage Drop (V))

Given:
Time (T) = 120 seconds
Capacitance (C) = 300 PF
Voltage Drop (V) = 300 V - 100 V = 200 V

Plugging in these values, we get:

R = (120 seconds * 300 PF) / 200 V
R = (120 * 300 * 10^-12) / 200
R = 0.18 * 10^-6

Therefore, the insulation resistance of the cable is 0.18 MΩ (megaohms).
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A length of cable was tested for insulation resistance using loss of charge method. A capacitance formed by sheath of cable of 300 PF is found to have drop in voltage from 300 V to 100 V in 120 seconds. Calculate the insulation resistance of the cable in MΩa)0.367 × 106MΩb)0.12 × 106MΩc)0.45 MΩd)0.45 × 106MΩCorrect answer is option 'A'. Can you explain this answer?
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