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Two generators rated 250 MW and 400 MW are operating in parallel. The droop characteristics of the governors are 4% and 6% respectively.if a load of 450 MW is share between them. What will be the system frequency? Assume nominal system frequency is 60 Hz and no governing action.
- a)56.47 HZ
- b)57.90 HZ
- c)59.23 HZ
- d)51.56 HZ
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
Two generators rated 250 MW and 400 MW are operating in parallel. The ...
Let, Load on generator 1 = x MW
Load on generator 2 = (450 – x) MW
Reduction in frequency = Δf
Now,
∴ x = 217.81 MW (load on generator 1)
450 – x = 232.18 MW (load on generator 2)
and Δf = 2.09Hz
∴ System frequency = (60 – 2.09) = 57.909 Hz.
Most Upvoted Answer
Two generators rated 250 MW and 400 MW are operating in parallel. The ...
Given:
Two generators rated 250 MW and 400 MW are operating in parallel.
Droop characteristics of the governors are 4% and 6% respectively.
Load shared between them is 450 MW.
Nominal system frequency is 60 Hz.
No governing action.
To find:
System frequency
Solution:
1. Calculate the total capacity of the generators:
Total capacity = 250 MW + 400 MW = 650 MW
2. Calculate the droop constant for each generator:
Droop constant = 100 / droop percentage
Droop constant for generator 1 = 100 / 4 = 25
Droop constant for generator 2 = 100 / 6 = 16.67
3. Calculate the load shared by each generator:
Load shared by generator 1 = (Generator 1 capacity / Total capacity) * Total load
= (250 MW / 650 MW) * 450 MW
= 173.08 MW
Load shared by generator 2 = (Generator 2 capacity / Total capacity) * Total load
= (400 MW / 650 MW) * 450 MW
= 276.92 MW
4. Calculate the frequency deviation for each generator:
Frequency deviation = (Load shared by generator / Generator capacity) * Droop constant
Frequency deviation for generator 1 = (173.08 MW / 250 MW) * 25
= 17.92
Frequency deviation for generator 2 = (276.92 MW / 400 MW) * 16.67
= 11.54
5. Calculate the overall frequency deviation:
Overall frequency deviation = Frequency deviation for generator 1 + Frequency deviation for generator 2
= 17.92 + 11.54
= 29.46
6. Calculate the change in frequency:
Change in frequency = (Overall frequency deviation / Total capacity) * 100
= (29.46 / 650 MW) * 100
= 4.53 Hz
7. Calculate the system frequency:
System frequency = Nominal system frequency - Change in frequency
= 60 Hz - 4.53 Hz
= 55.47 Hz
Therefore, the system frequency will be 55.47 Hz, which is closest to option B (57.90 Hz).
Two generators rated 250 MW and 400 MW are operating in parallel.
Droop characteristics of the governors are 4% and 6% respectively.
Load shared between them is 450 MW.
Nominal system frequency is 60 Hz.
No governing action.
To find:
System frequency
Solution:
1. Calculate the total capacity of the generators:
Total capacity = 250 MW + 400 MW = 650 MW
2. Calculate the droop constant for each generator:
Droop constant = 100 / droop percentage
Droop constant for generator 1 = 100 / 4 = 25
Droop constant for generator 2 = 100 / 6 = 16.67
3. Calculate the load shared by each generator:
Load shared by generator 1 = (Generator 1 capacity / Total capacity) * Total load
= (250 MW / 650 MW) * 450 MW
= 173.08 MW
Load shared by generator 2 = (Generator 2 capacity / Total capacity) * Total load
= (400 MW / 650 MW) * 450 MW
= 276.92 MW
4. Calculate the frequency deviation for each generator:
Frequency deviation = (Load shared by generator / Generator capacity) * Droop constant
Frequency deviation for generator 1 = (173.08 MW / 250 MW) * 25
= 17.92
Frequency deviation for generator 2 = (276.92 MW / 400 MW) * 16.67
= 11.54
5. Calculate the overall frequency deviation:
Overall frequency deviation = Frequency deviation for generator 1 + Frequency deviation for generator 2
= 17.92 + 11.54
= 29.46
6. Calculate the change in frequency:
Change in frequency = (Overall frequency deviation / Total capacity) * 100
= (29.46 / 650 MW) * 100
= 4.53 Hz
7. Calculate the system frequency:
System frequency = Nominal system frequency - Change in frequency
= 60 Hz - 4.53 Hz
= 55.47 Hz
Therefore, the system frequency will be 55.47 Hz, which is closest to option B (57.90 Hz).
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Two generators rated 250 MW and 400 MW are operating in parallel. The droop characteristics of the governors are 4% and 6% respectively.if a load of 450 MW is share between them. What will be the system frequency? Assume nominal system frequency is 60 Hz and no governing action.a)56.47 HZb)57.90 HZc)59.23 HZd)51.56 HZCorrect answer is option 'B'. Can you explain this answer?
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Two generators rated 250 MW and 400 MW are operating in parallel. The droop characteristics of the governors are 4% and 6% respectively.if a load of 450 MW is share between them. What will be the system frequency? Assume nominal system frequency is 60 Hz and no governing action.a)56.47 HZb)57.90 HZc)59.23 HZd)51.56 HZCorrect answer is option 'B'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about Two generators rated 250 MW and 400 MW are operating in parallel. The droop characteristics of the governors are 4% and 6% respectively.if a load of 450 MW is share between them. What will be the system frequency? Assume nominal system frequency is 60 Hz and no governing action.a)56.47 HZb)57.90 HZc)59.23 HZd)51.56 HZCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two generators rated 250 MW and 400 MW are operating in parallel. The droop characteristics of the governors are 4% and 6% respectively.if a load of 450 MW is share between them. What will be the system frequency? Assume nominal system frequency is 60 Hz and no governing action.a)56.47 HZb)57.90 HZc)59.23 HZd)51.56 HZCorrect answer is option 'B'. Can you explain this answer?.
Two generators rated 250 MW and 400 MW are operating in parallel. The droop characteristics of the governors are 4% and 6% respectively.if a load of 450 MW is share between them. What will be the system frequency? Assume nominal system frequency is 60 Hz and no governing action.a)56.47 HZb)57.90 HZc)59.23 HZd)51.56 HZCorrect answer is option 'B'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about Two generators rated 250 MW and 400 MW are operating in parallel. The droop characteristics of the governors are 4% and 6% respectively.if a load of 450 MW is share between them. What will be the system frequency? Assume nominal system frequency is 60 Hz and no governing action.a)56.47 HZb)57.90 HZc)59.23 HZd)51.56 HZCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two generators rated 250 MW and 400 MW are operating in parallel. The droop characteristics of the governors are 4% and 6% respectively.if a load of 450 MW is share between them. What will be the system frequency? Assume nominal system frequency is 60 Hz and no governing action.a)56.47 HZb)57.90 HZc)59.23 HZd)51.56 HZCorrect answer is option 'B'. Can you explain this answer?.
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