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Number of H+ ions present in 10 mL of a solution of pH =  3 is:
  • a)
    1013
  • b)
    6.02 x 1018
  • c)
    6.02 x 1013
  • d)
    6.02 x 1010
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
Number of H+ ions present in 10 mL of a solution of pH = 3 is:a)1013b)...
Meq. of H+ = 10-3 x 102
∴  No. of H+ =  
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Most Upvoted Answer
Number of H+ ions present in 10 mL of a solution of pH = 3 is:a)1013b)...
Solution:

To determine the number of H+ ions present in a solution, we need to use the definition of pH:


Given that the pH of the solution is 3, we can rearrange the equation to solve for [H+]:
[H+] = 10^(-pH)

Step 1: Calculate the value of [H+]
[H+] = 10^(-3) = 0.001

Step 2: Convert the volume of the solution to liters
10 mL = 10/1000 = 0.01 L

Step 3: Calculate the number of moles of H+ ions
Number of moles = concentration x volume
Number of moles = 0.001 mol/L x 0.01 L = 0.00001 mol

Step 4: Convert the number of moles to number of ions
Since 1 mole of H+ ions contains 6.02 x 10^23 ions, we can use this conversion factor:

Number of ions = number of moles x Avogadro's number
Number of ions = 0.00001 mol x 6.02 x 10^23 ions/mol = 6.02 x 10^18 ions

Therefore, the number of H+ ions present in 10 mL of a solution with a pH of 3 is 6.02 x 10^18.

Answer: Option B) 6.02 x 10^18.
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Number of H+ ions present in 10 mL of a solution of pH = 3 is:a)1013b)6.02 x 1018c)6.02 x 1013d)6.02 x 1010Correct answer is option 'B'. Can you explain this answer?
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